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Lostsunrise [7]
2 years ago
13

Identify the correct formula for each of the following acids. Click here to use the common polyatomic ion sheet if needed.

Chemistry
1 answer:
weeeeeb [17]2 years ago
4 0

Answer:

HCl

H3PO4

Explanation:

have a great day

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Calculate the number of kilojoules to warm 125 g of iron from 23.5 °C to 78.0 °C.
insens350 [35]
Given:
Iron, 125 grams T
1 = 23.5 degrees Celsius, T2 = 78 degrees Celsius.  

Required:
Heat produced in kilojoules  

Solution:
The molar mass of iron is 55.8 grams per mole. SO we need to change the given mass of iron into moles.  
 
Number of moles of iron = 125 g/(55.8 g/mol) = 2.24 moles  
<span>
Q (heat) = nRT = nR(T2 = T1)</span>
Q (heat) = 2.24 moles (8.314 Joules per mol degrees Celsius) (78.0 degrees Celsius – 23.5 degrees Celsius)
<u>Q (heat) = 1014.97 Joules or 1.015 kilojoules</u> <span>This is the amount of heat produced in warming 125 g f iron.</span>
7 0
3 years ago
What does it mean to classify?
pashok25 [27]

Answer:

2

Explanation:

to separate objects or ideas into group based on ways they are alike

3 0
2 years ago
3. Your company makes 1000 boxes of 500 g baking soda per day.
inessss [21]

500,000 g of baking soda is present in 1000 boxes of 500 g baking soda boxes.

Answer:

Option C.

Explanation:

As 500 g of baking soda is taken in each box of that company. The total weight of baking soda in all the boxes can be determined by adding the weights of each box. This is possible only when the number of boxes is less. But if the number of boxes are large, then we can determine the total weight of baking soda by multiplying the number of boxes with the weight in each box.

So in this case, 1000 boxes are present and in that 500 g of baking soda are present in each box.

So total grams of baking soda will be 1000 * 500 = 5,00,000 g.

Thus, 500,000 g of baking soda is present in 1000 boxes of 500 g baking soda boxes.

5 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
Predict the products and write balanced net ionic equations for the following reactions. (g) SnCl2 is added to KMnO4 solution (a
ch4aika [34]

Answer:

The answer to your question is:

Explanation:

Reaction

                  SnCl₂    +    2KMnO₄     ⇒    2 KCl     +    Sn(MnO₄)₂

                                               1 ----   Sn ----  1

                                               2 ----   K  ----- 2

                                               2 ----  Mn ----  2

                                               8 ----    O ----  8

                                               2 ----   Cl ----  2

6 0
3 years ago
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