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3 years ago

Does someone know the answer

Mathematics

1 answer:

seropon [69]3 years ago

7 0

11 square. units × 7 square. units × 1/2= B. 38.5 square. units.

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Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (

jek_recluse [69]

Answer:

There are no true solutions to the equation

Step-by-step explanation:

The equation is

y+1=√-2y-3

Find y

Square both sides

(y+1)^2=(√-2y-3)^2

y^2+2y+1= -2y-3

y^2+2y+1+2y+3=0

y^2+4y+4=0

Solve quadratic equation by factorisation

we have

(y+2)(y+2)=0

y=-2

Check

y+1=√-2y-3

-2+1=√-2(-2)-3

-1=√4-3

-1=√1

-1=1

This is not true

5 0

3 years ago

Describe the steps you would take to sketch the graph p(x)=2x^(3)+7x^(2)-3x-18

mojhsa [17]

Answer:

When we have a given function, y = f(x), the general way of graphing the function is finding a lot of coordinate pairs (x, f(x)) and graphing them in a coordinate axis, and then connect them.

So here we have:

p(x) = 2x^(3)+7x^(2)-3x-18

Just let's find the value of p(x) for different values of x, and let's do it.

p(0) = 2*0^(3)+7*0^(2)-3*0-18 = -18

Then the point (0, -18) belongs to the graph

p(1) = 2*1^(3)+7*1^(2)-3*1-18 = 2 + 7 - 3 - 18 = -12

then the point (1, - 12) belongs to the graph.

p(-1) = 2*(-1)^(3)+7*(-1)^(2)-3*(-1)-18 = -2 + 7 + 3 - 18 = -10

then the point (-1, -10) belongs to the graph:

p(2) = 2*2^(3)+7*2^(2)-3*2-18 = 16 + 28 - 6 - 18 = 20

Then the point (2, 20) belongs to the graph

p(-2) = 2*(-2)^(3)+7*(-2)^(2)-3*(-2)-18 = -16 + 28 + 6 - 18 = 0

Then the point (-2, 0) belongs to the graph.

p(-3) = 2*(-3)^(3)+7*(-3)^(2)-3*(-3)-18 = -54 + 63 + 9 - 18 = 0

Then the point (-3, 0) belongs to the graph.

Now that we have 6 points we can graph them and try to connect them.

We also know that this is a cubic polynomial, so we can expect that it changes its direction two times (no more than that) then knowing that we can estimate a shape for the graph, and you will obtain something like the graph of the image below, where I just connected the known points.