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Olegator [25]
3 years ago
5

Carol has only 20p and 10p coins in her purse she has three times as many 20p coins and 10p coins if Carol has ?4.20 altogether,

how many 20p coins does she have
Mathematics
2 answers:
irinina [24]3 years ago
7 0

Suppose that Carol has x 10p coins in her purse. Since she has three times as many 20p coins as 10p coins, then she has 3x 20p coins in her purse.

x coins of 10p value $0.10x and 3x coins of 20p value $0.60x.

In total this amount of money is $(0.10x+0.60x)=$0.70x that is exactly $4.20. Thus, you get the equation

0.70x=4.20.

Solve it:

x=\dfrac{4.20}{0.70}=6.

Carol has 6 coins of 10p and 3·6=18 coins of 20p.


Harman [31]3 years ago
4 0

Answer:

I'm not sure how euros work but I'm almost certain there are 18 20p coins

Step-by-step explanation:

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The number p and 2/3 are additive inverses.
vlada-n [284]

By knowing that p and 2/3 are additive inverses, we will see that p = -2/3

So two numbers A and B are additive inverses if:

A + B = 0

Here the two numbers are p and 2/3, so we have:

2/3 + p = 0

Solving this for p gives:

p = -2/3

Then the value of p is just -2/3.

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6 0
2 years ago
Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a
Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}

(a). Exactly one face up is red.

The odds of only the first die being red are:

P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}

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P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}

Thus, the probability that at least one die turns up red is:

P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}

4 0
3 years ago
A researcher wishes to conduct a study of the color preferences of new car buyers. suppose that 50% of this population prefers t
Amanda [17]
We will use the Binomial probability formula to find the answer

The formula is given by ⁿCₓ (p)ˣ (1-p)ⁿ-ˣ

We have
n, the number of trial = 16
x, the sample we aim to try = 7
p, the probability of success = 0.5

Substitute these values into the formula

P(7) = ¹⁶C₇ (0.5)⁷ (1-0.5)¹⁶⁻⁷
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3 0
3 years ago
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Yakvenalex [24]

Answer:

x^2 | y^25 |√187x

Step-by-step explanation:

First you simplify the equation then you factor 184 into its prime factors which is   184 = 23 • 23  

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8 0
2 years ago
8th grade math help!!
horsena [70]

Step-by-step explanation:

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5 0
2 years ago
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