The equation of line is:

Further explanation:
Given equation of line is:
y = 3x+5
The standard form of point-slope form is:
y = mx+b
Comparing the given equation with the standard form is:
m = 3
We know that product of slopes of two perpendicular lines is -1
Let m2 be the slope of line perpendicular to y = 3x+5
Then

Putting the value of slope in standard form

To find the value of b, putting (-3,-4) in equation

Putting the values of slope and b in equation

Keywords: Slope, Point-intercept form
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