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nekit [7.7K]
3 years ago
9

Can you please help me on 3n-2(-2-7n)=4(1-8n)

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

n = 0

Step-by-step explanation:

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Oceanside Bike Rental Shop charges an initial fee of 15 dollar plus 7 dollars an hour for renting a bike. Joan paid 57 dollars t
dlinn [17]

Answer:

6

Step-by-step explanation:

57=15+7x --> 57-15=7x --> 42=7x --> 42/7=x --> 6

6 0
3 years ago
Out of 28 students in a class, 7 have blue eyes. What is the probability a student picked at
mars1129 [50]

Answer:

3/4

Step-by-step explanation:

7/28 have blue eyes

So 28-7=21

21/28 don't have blue eyes

21/28 simplified=3/4

7 0
3 years ago
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The table represents a function.
mezya [45]

Answer:

-8

Step-by-step explanation:

You are given the following table representing the function f(x):

\begin{array}{cc}x&f(x)\\-4&-2\\-1&5\\3&4\\5&-8\end{array}

This means

f(-4)=-2\\ \\f(-1)=5\\ \\f(3)=4\\ \\f(5)=-8

Hence,

f(5)=-8

8 0
4 years ago
Read 2 more answers
Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

7 0
2 years ago
This table is proportional. What is the constant of proportionality?<br> k=
swat32

Answer:

huh

Step-by-step explanation:

5 0
3 years ago
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