Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
50% (170) since there’s only 2 opinion and that’s the only info it gives us
Answer:
Option D
Step-by-step explanation:
A reporter collects a random sample of 50 runners from all the runners who finished the Cherry Blossom Ten Mile Run in 2009 and constructs a 99% confidence interval for the true mean finish time to be (86.05, 99.38) minutes.
Assuming the reporter performed the calculations correctly, which of the following statements are appropriate interpretations of this confidence interval?
We can expect that 99% of confidence intervals created using the same method the reporter used will contain the true mean run time for runners of this race.
Answer:
its 34
Step-by-step explanation:
Answer:
Step-by-step explanation:
Step 1: Build the expression in numerical form.
Step 2: Distribute the negative sign.
Step 3: Combine like terms.
Therefore, the answer is 
.
