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Vesna [10]
3 years ago
15

Can somebody explain to me how I should do this ?

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

a. m = 3/2

b. m = -1/4

Step-by-step explanation:

Advocard [28]3 years ago
7 0

Answer:

In the equation of a straight line (when the equation is written as "y = mx + b"), the slope is the number "m" that is multiplied on the x, and "b" is the y-intercept (that is, the point where the line crosses the vertical y-axis). This useful form of the line equation is sensibly named the "slope-intercept form"

Step-by-step explanation:

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Nick has 3 shirts: a white one, a black one, and a blue one. He also has two pairs of pants, one blue and one tan. What is the p
Vikki [24]
There is a 1 out of 12, you could have a white shirt and blue pants and on and on with them all
5 0
2 years ago
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PLEASE ANSWERRRRRRRRRRRRRRRRRRR
DochEvi [55]
The answer is B.

I hope this helps!
7 0
3 years ago
The value of Peter's house has risen 20% a year for the last 3 years. If the value of Peter's home 3 years ago was $110,000.00,
IRISSAK [1]
Increase $110,000 by 20% 3 times.

110,000 x 0.2 = 22000
(0.2 is 20% as a decimal, we needed to convert it to multiply it)

So we must add 22000 to 110,000, then take 20% of the new cost, and repeat.

Add them
110,000 + 22000 = 132000

Take 20% of new value
132000 x 0.2 = 26400

Add that
132000 + 26400 = 158400

Take another 20% of that
31680

Add them
158400 + 31680 = 190080

So the value is now $190,080

A much more efficient way to do this would be multiplying 1.2 instead of 0.2, and skipping the adding part, as you already took 100% of it and are adding 20% more.

Hope this helps!
4 0
3 years ago
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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
Find the solutions to the equation below x^2-25=0
Arlecino [84]

Answer:

x=5,x=-5

Step-by-step explanation:

The screenshot below will explain the answer

3 0
3 years ago
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