Answer:
B.JK and LM meet at a 90 ° Angle
Step-by-step explanation:
Two lines are said to be perpendicular if they meet each other at right angle or 90 degrees.
It is given line JK is perpendicular to line LM.
So JK and LM meet each other at right angle or 90 degrees.
Among all the options given option B that is JK and LM meet at 90°is true.
C. 4 because 4 is a perfect square, as well as x^2 and 4x
I hope that helps!
Let us find the slopes of the two lines
ax+by=c, slope m1 = -a/b
bx-ay=c, slope m2 = b/a
m1*m2 = (-a/b)(b/a) = -1
Therefore the two lines are perpendicular so the answer is D
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
![y^ \frac{1}{5}= \sqrt[5]{y^1}= \sqrt[5]{y}](https://tex.z-dn.net/?f=y%5E%20%5Cfrac%7B1%7D%7B5%7D%3D%20%5Csqrt%5B5%5D%7By%5E1%7D%3D%20%5Csqrt%5B5%5D%7By%7D%20%20)