(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
-8y-67
Step-by-step explanation:
-7(y+9)-(y+4) distribute
-7y-63-y-4 combine like terms
-8y-67
i believe this is the right answer :D
Q1. Look at the picture.
Q2. Look at the picture.
Q3.
Put the value of x = 2 to the equation 3x + y = 5:
<em>subtract 6 from both sides</em>
Q4.
Substitute (*) to (**):
<em>use distributive property</em>
<em>add 33 to both sides</em>
<em>divide both sides by 11</em>
Put the value of m to (*):
Q5.
w - width
3w - length
24 in - the sum of length and width
The equation:
<em>divide both sides by 4</em>
Answer:
24
Step-by-step explanation:
18 * 4 /3 = 72/3 = 24
Using a graphical tool we obtain that the solution of this system
(intersection between the lines)
is given by the point
(x,y) = (2,4)
