The height of the kite above the ground will be 108.22m.
<h3>How to get the height?</h3>
From the information, the wind makes an angle of 56° to the ground and the kite is about 73m.
Therefore, the height of the kite above the ground will be:
Tan 56° = opposite/adjacent
1.48256 = x/73
x = 73 × 1.48256
x = 108.22m
Learn more about angles on:
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For this case we have the following transformation:

Using the transformation we have that the image is:

Therefore, making use of this information, we can find the coordinates of the pre-image
We have then:

From here, we clear x:

On the other hand we have:

From here, we clear y:

The coordinates of the pre-image is:
Answer:
A point that is the pre-image is:
Answer:
A
Step-by-step explanation:
(x+2)(x+2)
= x^2+2x+2x+4
=x^2+4x+4
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
x = -1
Step-by-step explanation:
in pic
<u><em>(Credits: Symbolab)</em></u>
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(Hope this helps can I pls have brainlist (crown)☺️)