Let X be a discrete binomial random variable.
Let p = 0.267 be the probability that a person does not cover his mouth when sneezing.
Let n = 18 be the number of independent tests.
Let x be the number of successes.
So, the probability that the 18 individuals, 8 do not cover their mouth after sneezing will be:
a) P (X = 8) = 18! / (8! * 10!) * ((0.267) ^ 8) * ((1-0.267) ^ (18-8)).
P (X = 8) = 0.0506.
b) The probability that between 18 individuals observed at random less than 6 does not cover their mouth is:
P (X = 5) + P (X = 4) + P (X = 3) + P (X = 2) + P (X = 1) + P (X = 0) = 0.6571.
c) If it was surprising, according to the previous calculation, the probability that less than 6 people out of 18 do not cover their mouths is 66%. Which means it's less likely that more than half of people will not cover their mouths when they sneeze.
We can use proportion to get the result
10 ----------- 5%
x ------------- 100%
Crossmultiply proportion
5*x=10*100
5x=1000 /:5 divide both sides by 5
x=1000:5
x=200 - its the answer
y =2x-1
Step-by-step explanation:
15% off means 85% on so I would use .85x · 6 = total monthly cost to represent this problem. The dot represents times (I did not want to confuse things by using x)
Other ways to express this:
6 x .85x
6(.85x)
.85x (6)
the measurement for 18.9 m is 0.05
