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yan [13]
3 years ago
13

Which of the following represents the additive inverse of 125? A. -(-125) B. 125 C. -125 D. 1/25

Mathematics
2 answers:
Elden [556K]3 years ago
7 0

Additive inverse of 125 is – 125, option C is correct.

<u>Solution:</u>

Given that , a number is 125

We have to find the additive inverse for the above given number from the above given set of options.

Now, we know that, <em>sum of a number and its additive inverse equals to 0. </em>

So, let us check option by option.

<em><u>Option A:</u></em>

Given number is -(-125)

-(-125) ⇒ 125 + ( - ( - 125 ) )  

⇒ 125 + 125  

⇒ 250 ⇒ wrong option

<em><u>Option B:</u></em>

Given number is 125

⇒ 125 + 125 ⇒ 250 ⇒ wrong option

<em><u>Option C:</u></em>

Given number is -125

125 + ( - 125 ) ⇒ 125 – 125  ⇒ 0 ⇒ correct option

Hence, additive inverse of 125 is – 125, option C is correct

Scrat [10]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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Answer:

a=200 +0.253*50=212.65

So the value of height that separates the bottom 60% of data from the top 40% is 212.65. And rounded would be 212.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the loan officer rates applicants for a credit of a population, and for this case we know the distribution for X is given by:

X \sim N(200,50)  

Where \mu=200 and \sigma=50

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.40   (a)

P(X   (b)

Both conditions are equivalent on this case.

As we can see on the figure attached the z value that satisfy the condition with 0.60 of the area on the left and 0.40 of the area on the right it's z=0.253. On this case P(Z<0.253)=0.60 and P(z>0.253)=0.4

If we use condition (b) from previous we have this:

P(X  

P(Z

But we know which value of z satisfy the previous equation so then we can do this:

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And if we solve for a we got

a=200 +0.253*50=212.65

So the value of height that separates the bottom 60% of data from the top 40% is 212.65. And rounded would be 212.7.  

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