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4 years ago

Which of the following represents the additive inverse of 125? A. -(-125) B. 125 C. -125 D. 1/25

Mathematics

2 answers:

Elden [556K]4 years ago

7 0

Additive inverse of 125 is – 125, option C is correct.

Solution:

Given that , a number is 125

We have to find the additive inverse for the above given number from the above given set of options.

Now, we know that, sum of a number and its additive inverse equals to 0.

So, let us check option by option.

Option A:

Given number is -(-125)

-(-125) ⇒ 125 + ( - ( - 125 ) )

⇒ 125 + 125

⇒ 250 ⇒ wrong option

Option B:

Given number is 125

⇒ 125 + 125 ⇒ 250 ⇒ wrong option

Option C:

Given number is -125

125 + ( - 125 ) ⇒ 125 – 125 ⇒ 0 ⇒ correct option

Hence, additive inverse of 125 is – 125, option C is correct

Scrat [10]4 years ago

5 0

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve using the quadratic formula. Approximate answers to the nearest tenth.

Thepotemich [5.8K]

Answer:

$\displaystyle x = 2, \ 3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $\displaystyle x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

Step 1: Define

Identify variables

x² - 5x + 6

↓

a = 1, b = -5, c = 6

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x = \frac{5 \pm \sqrt{(-5)^2-4(1)(6)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x = \frac{5 \pm \sqrt{25-4(1)(6)}}{2(1)}$
[√Radical] Multiply: $\displaystyle x = \frac{5 \pm \sqrt{25-24}}{2(1)}$
[√Radical] Subtract: $\displaystyle x = \frac{5 \pm \sqrt{1}}{2(1)}$
[√Radical] Evaluate: $\displaystyle x = \frac{5 \pm 1}{2(1)}$
Multiply: $\displaystyle x = \frac{5 \pm 1}{2}$
Add/Subtract: $\displaystyle x = \frac{4}{2}, \ \frac{6}{2}$
Divide: $\displaystyle x = 2, \ 3$