Triangle A
hypotenuse: 3y + x
leg: y - x
Triangle B
hypotenuse: y + 5
leg: x + 5
Congruency => 3y + x = y + 5 and y - x = x + 5
Solve the system
3y + x = y + 5 -> 2y + x = 5
y - x = x + 5 -> y - 2x = 5
2y + x = 5
-2y + 4x = -10
5x = -5
x = -1
y = (5 -(-1)) / 2 = 6/2 = 3
Verify:
hypotenuses
3y + x = 9 - 1 = 8
y + 5 = 3 + 5 = 8
Legs:
y - x = 3 -(-1) = 3 + 1 = 4
x + 5 = -1 + 5 = 4.
Then both hypotenuses and both legs are congruent.
Answer: x = -1 and y = 3
The polynomial function of the least degree with integral coefficient that has the given zeros is <span>y = (x+2)(x-2)(x-4)(x-6). I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications about the said problem.</span>
Expand by multiplying out:
14-15t + 36 = 1 -20t -1,
Because of the minus before the bracket, it changes the sign inside the bracket
-15t + 20t = 1-1-14-36 Rearranging the ts on one side and the numbers on other
side.
5t = -50 Divide both sides by 5.
t = -50/5
t = -10.
Answer:
x = 2, x = -5/2
Step-by-step explanation:
2x² + x - 10 = 0
(2x + 5)(x - 2) = 0
2x + 5 = 0
2x = -5
x = -5/2
x - 2 = 0
x = 2
