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dem82 [27]
2 years ago
6

Which of these numbers is a square number? What is question 3?

Mathematics
1 answer:
Vesnalui [34]2 years ago
4 0
B cause 9x10 to the 4 equals 90000 and if u square it, it will give u 300 but the rest is decimals
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Area of a rectangular field is 2c^3-c^2+6 square units. If the length of the field is c-2 units, what is its width ?
Tema [17]
If you just factor the original polynomial(The area) then you will find that one of the factors is c-2(the length) and the other will be the width.
When I factored it, I got 2c+3 as the width.
:)
6 0
3 years ago
An international company has 13,600 employees in one country. If this represents 19.3% of the company's employees, how many empl
user100 [1]
Hi there! To solve this question, we can write and solve a proportion. Let’s set it up like this: 13,600/x = 19.3/100. We do this, because we’re looking for the total amount of people, which would be the whole. We already have the part. Cross multiply the values in order to get 1,360,000 = 19.3x. Now, divide each side by 19.3 to isolate the variable. When you do, you get x is approx. 70,466.3212 or 70,466 when rounded to the nearest whole number. Plus, you can’t have a fraction of a person, anyway. The company has a total of 70,466 employees.
4 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
2 years ago
Brett has a $30 online gift certificate. He plans to buy as many books as he can. The cost of each book is $4. There is also a s
kkurt [141]

Answer:

7 books

Step-by-step explanation:

make an equation

x = # of books each book is $4 so its 4x

the shipping fee no matter how many books he buys will be $2 so it's just 2

the equation looks like this:

4x + 2 = 30

we set equal to 30 cuz he can't spend more than $30

solve for x

4x = 30 -2

4x = 28

x = 7

Brett can buy no more than 7 books.

7 0
3 years ago
a bean plant was 15 centimeters tall one week ago. In 5 days it grew 1 meter. find the current height of the plant.
Likurg_2 [28]
The plant is currently 115 centimeters high
4 0
3 years ago
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