Question

The sum of two numbers is 47, and their difference is 15. The larger number is

Answer 1

Answer:

The large number is 31, and the small number is 16

Step-by-step explanation:

Given data

let the first number be x

and the second number be y

so

x+y= 47------------1

and

y-x= 15-------------2

from eqn1

x= 47-y

put this in eqn 2

y-(47-y)=15

y-47+y=15

2y= 15+47

2y=62

divide both side by 2

x= 62/2

x=31

From eqn 1

x+y= 47

31+y=47

y=47-31

y=16