The sum of two numbers is 47, and their difference is 15. The larger number is
1 answer:
Answer:
The large number is 31, and the small number is 16
Step-by-step explanation:
Given data
let the first number be x
and the second number be y
so
x+y= 47------------1
and
y-x= 15-------------2
from eqn1
x= 47-y
put this in eqn 2
y-(47-y)=15
y-47+y=15
2y= 15+47
2y=62
divide both side by 2
x= 62/2
x=31
From eqn 1
x+y= 47
31+y=47
y=47-31
y=16
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