Answer:
The length of the diagonal HJ is 10.82 units
Step-by-step explanation:
* Lets revise the rule of the distance between two points
- 
, where
and 
are the two points
* Lets use this rule to find the length of the diagonal HJ
∵ The coordinates of point H are (-4 , 3)
∵ The coordinates of point J are (5 , -3)
∴ 
and 
∴ 
and 
- Lets find the length of the diagonal HJ by using the rule above
∴ HJ = 
∴ HJ = 
∴ HJ = 10.82
* The length of the diagonal HJ is 10.82 units
First,
We are dealing with parabola since the equation has a form of,
Here the vertex of an up - down facing parabola has a form of,
The parameters we have are,
Plug them in vertex formula,
Plug in the 
into the equation,
We now got a point parabola vertex with coordinates,
From here we emerge two rules:
- If
then vertex is max value - If
then vertex is min value
So our vertex is minimum value since,
Hope this helps.
r3t40
1. 6.73 x 10^6
2. 1.33 x 10^4
3.9.77 x 10^22
4. 3.84 x 10^5
The rest i didn’t understand what where you trying to say
Answer:
Hey there!
5(v+3)-10v>-10
5v+15-10v>-10
-5v+15>-10
-5v>-25
v<5
Let me know if this helps :)
Answer:
Step-by-step explanation:
The area of this parallelogram is
A=hb (height times base)
h=A/b, we see A=14.4mi^2 and b=4.8mi so
h=(14.4mi^2)/(4.8mi)
h=3 mi
