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3 years ago

Which of the Moon’s positions will cause the highest or spring tides?

Physics

2 answers:

olya-2409 [2.1K]3 years ago

7 0

The answer is B. A and C. Spring tides occur during a new moon and full moon

Contact [7]3 years ago

5 0

Answer:

Positions A and C will cause the highest tides, called spring tides, because the gravity of the Moon and Sun will work together to create the two tidal bulges on opposite sides of Earth. So B.

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_____ heat provides energy for thunderstorms and hurricanes. Polar Geothermal Nuclear Latent

NikAS [45]

The correct answer is Latent. Latent heat provides energy for thunderstorms and hurricanes. Hurricanes are a low pressure that is formed in warm oceans and the source of this energy is water vapor. Water vapor serves to be the food to the hurricanes because they release the latent heat of condensation.

4 0

3 years ago

A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0

3 years ago

The mass of earth 6*10^24kg its radius is 6.4*10^3km now calculate due to gravity on earth<br>

irga5000 [103]

Answer:

Explanation:

in your textbook, they have a formula like this:

g=mass of earth*G/R^2

G=6.67*10^-11

apply to this

we have g=6*10^2*4*6.67*10^-11/(6.4*10^3*1000)^2=9.78

7 0

3 years ago

The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the

Bad White [126]

Answer: c)• 2/3

Explanation:

Lets say q1 and q2 are two charges with r distance far apart.

So electrostatic force

F = (k q1 q2) / r²

as k = Coulomb's constant

Now

q1' = 2q1

q2' = q2/3

Therefore the new electrostatic force

F' = (k q'1 q'2) / r²

F' = (k 2q1 q2) / 3r²

F' = 2/3 [(k q1 q2) / r²]

so F' = 2/3F

New electrostatic force is 2/3F

3 0

3 years ago

I need help fast! !!!

I am Lyosha [343]

I think it would be at 3 or 6 but I would go with 3 not really sure tho

3 0

3 years ago