In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.1. What is the

Question

tino4ka555 [31]

3 years ago

5

In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.1. What is the

frequency of individuals with AA genotype?A) 0.42B) 0.20C) 0.32D) 0.81

Biology

1 answer:

Sati [7] · Answer 1 · 2022-07-15T06:23:56+03:00

The correct answer is D) 0,81

When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. And we have:

p²+2*p*q+q²= 1 <em>p+q= 1 p=1-q</em>

q= 0.1 p= 1-0.1= 0.9

p²=0.9²= 0.81