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Mila [183]
3 years ago
6

What structures are formed when water molecules surround ions

Chemistry
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

Solvation shells  

Explanation:

Ionic compounds like NaCl dissolve in polar solvents like water.

There are strong ion-dipole attractions between the ions and the water molecules.

The Na⁺ ions attract the negative oxygen atoms of water. The Cl⁻ ions attract the positive hydrogen atoms of water. The ions become surrounded by a solvation shell of water molecules.

The closer the opposite charges can get to each other, the more stable the system. That's why solvation stabilizes the ions.

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How many moles are in 64.8 g of ZnCl ?
ivann1987 [24]

Answer:

at least 1

Explanation:

7 0
3 years ago
A zinc rod is placed in 0.1 MZnSO4 solution at 298 K. Write the electrode reaction and calculate the potential of the electrode.
yanalaym [24]

<u>Answer:</u> The potential of electrode is -0.79 V

<u>Explanation:</u>

When zinc is dipped in zinc sulfate solution, the electrode formed is Zn^{2+}(aq.)/Zn(s)

Reduction reaction follows:  Zn^{2+}(0.1M)+2e^-\rightarrow Zn(s);(E^o_{Zn^{2+}/Zn}=-0.76V)

To calculate the potential of electrode, we use the equation given by Nernst equation:

E_{(Zn^{2+}/Zn)}=E^o_{(Zn^{2+}/Zn)}-\frac{0.059}{n}\log \frac{[Zn]}{[Zn^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = -0.76 V

n = number of electrons exchanged = 2

[Zn]=1M    (concentration of pure solids are taken as 1)

[Zn^{2+}]=0.1M

Putting values in above equation, we get:

E_{cell}=-0.76-\frac{0.059}{2}\times \log(\frac{1}{0.1})\\\\E_{cell}=-0.79V

Hence, the potential of electrode is -0.79 V

4 0
3 years ago
BRAINLIEST IF CORRECT
Airida [17]

Answer:

When water vapor in the air comes into contact with something cool, its molecules slow down and get closer together.

Explanation:

I hate it when you accidently drop your drink haha. Have a good day!!

3 0
3 years ago
Read 2 more answers
Can somebody help me out with this question?
KengaRu [80]

Answer:

3 element

Explanation:

H2SO4  has 2 hydrogen atom, 1 sulfur atom, 4 oxygen atoms that are chemically bonded.

5 0
3 years ago
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For each of the following pairs of compounds, name one absorption band that could be used to distinguish between them. CH3CH2OH
GrogVix [38]

Answer:

For CH3CH2OH the OH stretch between 3550-3200 cm-1

For CH3CH2NH2 a pair of bands at 3500 and 3400 cm-1 respectively corresponding to the N-H stretch

Explanation:

CH3CH2OH is ethanol. This is a primary alcohol characterized by the by the -OH (hydroxyl) group. A strong broad IR absorption in the 3550 - 3200 cm-1 corresponds to the O-H stretch and indicates that the compound could be an alcohol or it has an OH functional group.

CH3CH2NH2 is ethylamine. This is a primary amine characterized by the -NH2 (amino) group. The presence of a primary amine shows up as a pair of medium strength absorption features corresponding to the N-H stretch, one at around 3500 cm-1 and the other around 3400 cm-1.

7 0
3 years ago
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