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melisa1 [442]
3 years ago
8

CH4 (g) yields C(g) + 4H (g) (reaction for expansion)

Chemistry
2 answers:
anyanavicka [17]3 years ago
5 0

Answer:

Here's what I find.

Explanation:

\rm CH$_{4}$(g) $\, \rightleftharpoons \,$ C(g) + 4H(g)

\text{Same} =\begin{cases}1. & \text{The number of atoms of each element}\\2. & \text{The state of the methane molecules}\\4. &\text{The state of the carbon atoms}\\\end{cases}

\text{Different} =\begin{cases}3. & \text{The enthalpy change of the reaction}\\\end{cases}

The sign of ΔH changes when you reverse the reaction.  

Gala2k [10]3 years ago
4 0

Answer:

Same:

-the number of atoms

of each element

-the state of the

methane molecules

Different:

-the state of the

carbon atoms

-the enthalpy change

of the reaction

Explanation:

The enthalpy changes are different for the two reactions even though all the same elements are involved in equal numbers. This illustrates that the enthalpy change of a reaction is dependent on the states of the reactants and products, as well as how the atoms are bonded.

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What mass of carbon dioxide is produced from the complete combustion of 5.30x10-3 g of methane?
pshichka [43]

Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

Combustion of Methane:

1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

8 0
2 years ago
Does volume alone determine whether an object will sink or float? Explain.
Bond [772]

Answer:

no.

Density (mass / volume) determines whether an object floats or sinks. If the object is less dense than the medium in which it has been submerged, it floats. if it is more dense, it sinks. Volume will definitely determine if a steel ship floats, as steel is far more dense than water.

#FreeMelvin

3 0
3 years ago
Read 2 more answers
2.41 x 10^2 Cm to meters
Assoli18 [71]

We know that there are 100 cm in 1 m, so we can use this to convert to meters:

(\frac{2.41x10^{2}cm}{1})*(\frac{1m}{100cm} )=2.41m

Therefore we know that 2.41x10^{2} cm is equal to 2.41 m.

8 0
3 years ago
Read 2 more answers
A student was asked to prepare 500.0 mL of 6.0 M NaOH. The student measured 120.0 g of NaOH and placed it in a 1000 mL beaker. T
Morgarella [4.7K]

Answer:

The concentration of the solution will be much lower than 6M

Explanation:

To prepare a solution of a solid, the appropriate mass is taken and accurately weighed in a weighing balance and then made up to mark with distilled water.

From

n= CV

n = number of moles m/M( m= mass of solid, M= molar mass of compound)

C= concentration of substance

V= volume of solution

m=120g

M= 40gmol-1

V=500ml

120/40= C×500/1000

C= 120/40× 1000/500

C=6M

This solution will not be exactly 6M if the student follows the procedure outlined in the question. The actual concentration will be much less than 6M.

This is because, solutions are prepared in a standard volumetric flask. Using a 1000ml beaker, the student must have added more water than the required 500ml thereby making the actual concentration of the solution less than the expected 6M.

7 0
3 years ago
What is the error in the electron configuration, 1s2 2s2 2p6 3s2 3p5 4s2?
Leviafan [203]
1s2 2s2 2p6 3s2 3p6 4s1

s orbital can hold 2 electron
p orbitals can hold 6 electron
3 0
3 years ago
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