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2 years ago

Write the number shown on the calculator display in standard form.

Mathematics

1 answer:

frez [133]2 years ago

3 0

Answer:

2 Because visual specialization skills are important to success in so many career

fields, it is helpful to continue to build skill. What is one strategy you can use to

continue to improve your visualization skills?

Please someone help!!!

Step-by-step explanation:

2 Because visual specialization skills are important to success in so many career

fields, it is helpful to continue to build skill. What is one strategy you can use to

continue to improve your visualization skills?

Please someone help!!!

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Seven times a number is the same as 12 more than 3 times the number

Brums [2.3K]

Answer:

x=3

Step-by-step explanation:

7x=12+3x

4x=12

x=3

5 0

2 years ago

If f(x) = 3x - 2 and g(x) = 2x + 1, find (f - g)(x)

morpeh [17]

Answer:

(f-g)(x) = x-3

Step-by-step explanation:

Given

f(x) = 3x-2

and

g(x) = 2x+1

We have to find (f-g)(x)

So,

(f-g)(x) = f(x)-g(x)

= 3x-2 - (2x+1)

= 3x-2-2x-1

=x-3

Hence,

(f-g)(x) = x-3

6 0

3 years ago

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What is the answer to 1014.16667 rounded to the nearest tenths

yan [13]

Answer: 1014.2

Step-by-step explanation: you look to the right of 1 and if it is 5 or greater you round up. If it is 4 or less you keep it the same number as it is.

6 0

2 years ago

Find ∅ round to the nearest degree <br>A. 24° <br>B. 66° <br>C. 64° <br>D. 26°

Katyanochek1 [597]

Answer:

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosθ = $\frac{adjacent}{hypotenuse}$ = $\frac{7}{16}$ , then

θ = $cos^{-1}$ ( $\frac{7}{16}$ ) ≈ 64° ( to the nearest degree )

7 0

2 years ago

The picture shows a triangular island:

sergiy2304 [10]

Answer:

The expressions that show the value of q are

1) $q=\sqrt{r^{2}+s^{2}}$

2) $q=\frac{s}{cos(55\°)}$

3) $q=\frac{r}{sin(55\°)}$

4) $q=\frac{s}{sin(35\°)}$

5) $q=\frac{r}{cos(35\°)}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

case A)

In the right triangle of the figure

Applying the Pythagoras Theorem

$q^{2}=r^{2}+s^{2}$

$q=\sqrt{r^{2}+s^{2}}$

case B)

In the right triangle of the figure

$cos(55\°)=\frac{s}{q}$

solve for q

$q=\frac{s}{cos(55\°)}$

case C)

In the right triangle of the figure

$sin(55\°)=\frac{r}{q}$

solve for q

$q=\frac{r}{sin(55\°)}$

case D)

In a right triangle

if $A+B=90\°$

then

$cos(A)=sin(B)$

therefore

$q=\frac{s}{cos(55\°)}$ ------> $q=\frac{s}{sin(35\°)}$

$q=\frac{r}{sin(55\°)}$ ------> $q=\frac{r}{cos(35\°)}$

4 0

3 years ago

Read 2 more answers