If f(x) = 3^x + 10x and g(x) = 2x - 4, find (f + g)(x)

Mathematics

2 answers:

GuDViN [60]3 years ago

7 0

Answer:

The value of the function (f + g)(x) is $3^{x}+12x -4$ .

Option (D) is correct .

Step-by-step explanation:

As given the equation in the question be as follow.

$f(x) = 3^{x} + 10x$

g(x) = 2x - 4

Thus

(f + g)(x) = f(x) + g(x)

$(f + g)(x)= 3^{x}+10x +2x -4$

Simplify the above

$(f + g)(x)= 3^{x}+12x -4$

Therefore the value of the function (f + g)(x) is $3^{x}+12x -4$ .

Option (D) is correct .

kow [346]3 years ago

6 0

Answer:

The Answer is D

Step-by-step explanation:

All you do is add both equations 3^x+10x+2x-4

then you add the like varibles which is 10x+2x=12x

So, the answer is 3^x+12x-4

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2/3 cup of oatmeal is needed to make 10 granola bars. how many such granola bars can be made with 20 cups of oatmeal? Kindly ple

aleksandrvk [35]

2/3 cup of oatmeal - 10 granola bars

When the number of cups of oatmeal increases, the number of granola bars also increases.
If you use for example twice as many cups of oatmeal, you'll make twice as many granola bars.
Therefore, the first step is to calculate how many times 20 cups of oatmeal is more than 2/3 cup of oatmeal. To do it, divide 20 by 2/3.

$20 \div \frac{2}{3} = 20 \times \frac{3}{2}=\frac{60}{2}=30$

You have 30 times as many cups of oatmeal, so you'll make 30 times as many granola bars.

$10 \times 30= 300$

300 granola bars can be made with 20 cups of oatmeal.

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2 years ago

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mojhsa [17]

Answer:

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