Question

Solve with the substitution method -6x+4=33 5x+18y=29

Answer 1

You have to solve for  1 variable
I'm pretty sure they want 4y and not just y becaseu taht is too easy

-6x+4y=33
5x+18y=29

solve for 1 variable

may be messy
-6x+4y=33
add 6x both sides
4y=33+6x
divide both sides by 4
y=(33+6x)/4
sub that for y in other equation

5x+18((33+6x)/4)=29
5x+9(33+6x)/2=29
5x+(297+54x)/2=29
(10x/2)+(297+54x)/2=29
times both sides by 2
10x+297+54x=58
297+64x=58
minus 297 both sides
64x=-239
divide both sides by 64
x=-239/64
sub back

y=(33+6x)/4
y=(33+6(-239/64))/4
y=(33-717/32)/4
y=(1056/32-717/32)/4
y=(339/32)/4
y=339/128


the solution is
$( \frac{-239}{64}, \frac{339}{128})$
you can graph it and check if you want