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Lina20 [59]
3 years ago
15

Patrick is building a patio in the shape of a decagon with a radius of 12 feet. To determine the amount of cement needed, he mus

t first find the area.

Mathematics
1 answer:
kupik [55]3 years ago
5 0

Answer:

The area of the Patrick's building is 2340.22 ft^2.

Step-by-step explanation:

Shape of the Patrick's building = Decagon

In the figure attached:

Radius of the decagon = r = 12 feet

Side of the decagon = a

Angle AOB = 36°

Using trigonometric ratio is triangle AOC :

AO = r = 12 feet

AC = \frac{a}{2}=0.5a

\tan \theta=\frac{Perpendicular}{base}

\tan 36^o=\frac{0.5a}{12 feet}

a=\frac{\tan 36^o\times 12 feet}{0.5}=17.44 feet

Area of decagon :

A=\frac{5}{2}a^2\times \sqrt{5+2\sqrt{5}}

A=\frac{5}{2}(17.44 ft)^2\times \sqrt{5+2\sqrt{5}}

A=2340.22 ft^2

The area of the Patrick's building is 2340.22 ft^2.

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becayse if you ultipy 5 and three you get 15.

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Stuart paid $ 48.00 for a New tennis racket ,which was 64% of the original price what was the original price of the racket.
Trava [24]
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3 years ago
What is the quotient when the sum of 1,2 and 3 is divided by the product of 1,2 and 3
nexus9112 [7]

Answer: 1

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sum = add

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5 0
3 years ago
Read 2 more answers
Select the correct answer.
zysi [14]

Answer:

A.  -5x = -23

Step-by-step explanation:

First you have to simplify the equation - 4(x - 5) + 8x = 9x - 3

-4x + 20 + 8x = 9x -3

9x - 4x = 20 + 3

5x = 23

=> equivalent to answer A.

8 0
2 years ago
The time intervals between successive barges passing a certain point on a busy waterway have an exponential distribution with me
lisov135 [29]

Answer:

a) <u>0.4647</u>

b) <u>24.6 secs</u>

Step-by-step explanation:

Let T be interval between two successive barges

t(t) = λe^λt where t > 0

The mean of the exponential

E(T) = 1/λ

E(T) = 8

1/λ = 8

λ = 1/8

∴ t(t) = 1/8×e^-t/8   [ t > 0]

Now the probability we need

p[T<5] = ₀∫⁵ t(t) dt

=₀∫⁵ 1/8×e^-t/8 dt

= 1/8 ₀∫⁵ e^-t/8 dt

= 1/8 [ (e^-t/8) / -1/8 ]₀⁵

= - [ e^-t/8]₀⁵

= - [ e^-5/8 - 1 ]

= 1 - e^-5/8 = <u>0.4647</u>

Therefore the probability that the time interval between two successive barges is less than 5 minutes is <u>0.4647</u>

<u></u>

b)

Now we find t such that;

p[T>t] = 0.95

so

t_∫¹⁰ t(x) dx = 0.95

t_∫¹⁰ 1/8×e^-x/8 = 0.95

1/8 t_∫¹⁰ e^-x/8 dx = 0.95

1/8 [( e^-x/8 ) / - 1/8 ]¹⁰_t  = 0.95

- [ e^-x/8]¹⁰_t = 0.96

- [ 0 - e^-t/8 ] = 0.95

e^-t/8 = 0.95

take log of both sides

log (e^-t/8) = log (0.95)

-t/8 = In(0.95)

-t/8 = -0.0513

t = 8 × 0.0513

t = 0.4104 (min)

so we convert to seconds

t = 0.4104 × 60

t = <u>24.6 secs</u>

Therefore the time interval t such that we can be 95% sure that the time interval between two successive barges will be greater than t is <u>24.6 secs</u>

6 0
3 years ago
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