Bill changes £450 from his bank and gets $729.

Mathematics

1 answer:

Kobotan [32]2 years ago

8 0

Answer:

Bill got more ($1.62) for each pound exchanged than did Gwyll ($1.56).

Step-by-step explanation:

Let's calculate the unit rate in each case, that is, the number of dollars obtained through exchanging one (1) pound for dollars:

Bill:

$729

--------- = $1.62 per pound

£450

Gwyll:

$780

---------- = $1.56 per pound

£500

Bill got more ($1.62) for each pound exchanged than did Gwyll ($1.56).

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What is the differance look at the link

Luba_88 [7]

Answer:

The difference is $\frac{3}{4}$ inches.

Step-by-step explanation:

See the attached number line where the worm lengths in inches are plotted.

From the number line plotted in the attached photo, it is clear that the shortest worm has the length of $\frac{3}{4}$ inches and the longest worm has the length of $1\frac{1}{2}$ inches i.e. $\frac{3}{2}$ inches.

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2 years ago

Miki prepared two gallons of a beverage that contains tea and lemonade in the ratio tea:lemonade=3:1. If Miki then added one-hal

Advocard [28]

Ratio of tea to lemonade in the new mixture is 3 : 2

<h3><u>Solution:</u></h3>

Given that volume of a beverage prepared by Miki containing tea and lemonade = 2 gallons

Ratio of tea and lemonade in beverage prepared by Miki = 3:1

Then Miki added one half of gallon of lemonade to the mixture.

Need to determine ratio of tea and lemonade in the new mixture.

Lets first calculate volume of tea and volume of lemonade in old mixture that is the one before adding one half of gallon of lemonade.

Given ratio of tea and lemonade in old mixture = 3: 1 , means our of every four parts of mixture, 3 parts are of tea and 1 part is of lemonade.

$=>\text { In old mixture, } \frac{3}{4} \text { is tea and } \frac{1}{4} \text { is lemonade. }$

$\text { Volume of tea in old mixture }=\frac{3}{4} \times \text { volume of old mixture }=\frac{3}{4} \times 2 \text { gallons }=1.5 \text { gallons }$

$\text { Volume of lemonade in old mixture }=\frac{1}{4} \times \text { volume of old mixture }=\frac{1}{4} \times 2 \text { gallons }=0.5 \text { gallons }$