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Wewaii [24]
3 years ago
15

Why does the reaction H2O + Cu→no reaction not proceed to a product?

Chemistry
2 answers:
fiasKO [112]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

It is known that a stronger element is able to displace a less stronger element in a chemical reaction.

And, according to the reactivity chart hydrogen is more reactive in nature than copper.

Therefore, when Cu is added to H_{2}O then there will be no reaction because copper is less reactive than hydrogen.

Thus, we can conclude that the reaction H_{2}O+Cu \rightarrow \text{no reaction} not proceed to a product because copper has a lower activity than hydrogen and cannot replace it.

irina1246 [14]3 years ago
5 0
Copper has a lower activity than hydrogen
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Answer:

C

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Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

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First we have to calculate the moles of titanium(II) sulfide.

\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles

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From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}

\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g

To calculate the percentage yield of titanium (II) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

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Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

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