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ANEK [815]
2 years ago
12

How do you find the mass of original KClO3 sample

Chemistry
1 answer:
emmasim [6.3K]2 years ago
5 0
You cannot find it if you do not know the information.  Was there a molar mass given or do you know if it is asking for the molar mass?
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Force and distance are used to calculate work, work is measured in
Natali [406]
Work is measured in joules. hope this helps!
7 0
2 years ago
Read 2 more answers
How many moles of CH4 are in 148.6 g? Round your answer to two decimal places.
Dafna1 [17]

Answer:

9.29 mol

Explanation:

Given data:

Number of moles = ?

Mass = 148.6 g

Solution:

Number of moles = mass/ molar mass

Molar mass of CH₄ = 16 g/mol

Now we will put the values in formula.

Number of moles = 148.6 g/ 16 g/mol

Number of moles = 9.29 mol

Thus 148.6 g have 9.29 moles.

6 0
2 years ago
Reaction of (r)-2-chloro-4-methylhexane with excess nai in acetone gives racemic 2-iodo-4-methylhexane. what is the explanation
saveliy_v [14]

I believe this question has the following five choices to choose from:

 

>an SN2 reaction has occurred with inversion of configuration

>racemization followed by an S N 2 attack

>an SN1 reaction has taken over resulting in inversion of configuration

>an SN1 reaction has occurred due to carbocation formation

>an SN1 reaction followed by an S N 2 “backside” attack

 

 

The correct answer is:

an SN1 reaction has occurred due to carbocation formation 

4 0
3 years ago
In the experiment, 40 mL of 3 M sodium hydroxide is used to extract the benzoic acid. In order to recover the benzoic acid from
nikdorinn [45]

Answer:

20 mL OF 6 M HYDROCHLORIC ACID WILL BE NEEDED

Explanation:

M1 V1 = M2 V2

M1 = Molarity of sodium hydroxide = 3 M

V1 = volume of sodium hydroxide = 40 mL

M2 = Molarity of hydrochloric acid = 6 M

V2 = Volume of hydrochloric acid = unknown

Rearranging the equation, we have:

V2 = M1 V1 / M2

V2 = 3 * 40 mL / 6

V2 = 120 / 6

V2 = 20 mL

To precipitate the benzoic acid by 6 M of hydrochloric acid, 20 mL volume will be needed.

6 0
3 years ago
A solution is prepared by dissolving 0.23 mol of lactic acid and 0.27 mol of sodium lactate in water sufficient to yield 1.00 L
PtichkaEL [24]

Explanation:

The solution of the lactic acd and sodium lactate is referred to as a buffer solution.

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. In this case, the weak acid is the lactic acid and the conjugate base is the sodium lactate.

Buffer solutions are generally known to resist change in pH values.

When a strong base (in this case, NaOH) is added to the buffer, the lactic acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base, so we have:

HA + OH- → A- + H2O.

Since the added OH- is consumed by this reaction, the pH will change only slightly.

The NaOH reacts with the weak acid present in the buffer sollution.

6 0
3 years ago
Read 2 more answers
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