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anygoal [31]
3 years ago
7

Find the equation for the circle with a diameter whose endpoints are​ (1​,-2​) and ( 2, 5)

Mathematics
1 answer:
alekssr [168]3 years ago
7 0

Answer:

((1 + 2)/2 , (-2 + 5)/2) = (1.5 , 1.5)

(1.5 - 1)^2 + (1.5 - (-2))^2 = 12.5

Circle

(x - 1.5)^2 + (y - 1.5)^2 = 12.5

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3 years ago
Suppose the inside bottom of a box is painted with three colors: one-third of the bottom area is blue, one-sixth is red, and one
miss Akunina [59]

Answer:

The probability that the pebble will NOT land on color blue is 0.67.

Step-by-step explanation:

We attribute the box area as the probability of the events.

So the probability of landing in the Red Area is 1/6, the probability of landing in the Blue Area is 1/3 and the probability of landing in the Yellow Area is 1/2.

P(Red)=\frac{1}{6}

P(Yellow)=\frac{1}{2}

P(Blue)=\frac{1}{3}

The probability of landing in NOT Blue area is given by:

P(Not Blue)=1-P(Blue)=1-\frac{1}{3}=\frac{2}{3} =0.67

8 0
3 years ago
What is significant about circles that provides us with an equilateral triangle?
Ipatiy [6.2K]

Answer:

The circle is important when constructing equilateral triangles because it can allow one to draw an accurate triangle while not having a ruler to measure it out.

Step-by-step explanation:

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3 years ago
What is the factored form of y=x^3+3x^2-x-3 and what the zeros
PSYCHO15rus [73]
   y = x³ + 3x² - x - 3
   0 = x³ + 3x² - x - 3
   0 = x²(x) + x²(3) - 1(x) - 1(3)
   0 = x²(x + 3) - 1(x + 3)
   0 = (x² - 1)(x + 3)
   0 = (x² + x - x - 1)(x + 3)
   0 = (x(x) + x(1) - 1(x) - 1(1))(x + 3)
   0 = (x(x + 1) - 1(x + 1))(x + 3)
   0 = (x - 1)(x + 1)(x + 3)
   0 = x - 1    or    0 = x + 1    or    0 = x + 3
+ 1      + 1         - 1        - 1         - 3        - 3
   1 = x      or      -1 = x       or      -3 = x

Solution Set: {-3, -1, 1}
3 0
3 years ago
A store advertises 15% off an item that regularly sells $300. How is a 15% discount similar to a 15% decrease? Explain.
Kobotan [32]
Both a discount and decrease will make the cost the same which is $225 for the object. I think that's what your asking. I'm sorry if it is not that helpful.
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3 years ago
Read 2 more answers
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