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sveticcg [70]
4 years ago
6

Translate the sentence and solve: "4 is 2 less than double a number".

Mathematics
1 answer:
Elanso [62]4 years ago
4 0

Answer: x = 3

Step-by-step explanation:

you would double each number meamong multiply by 2 until you get the opposite of 4 being 2 less of a number so 6.

3 x 2 = 6

and 2 less than 6 is 4 so theres your answer :)

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Are of circle find. ​
Andreas93 [3]

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379.94

Step-by-step explanation:

11 squared is 122

Times 3.14 is 379.94

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3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
pashok25 [27]

Answer with Step-by-step explanation:

We are given that

f(x,y,z)=10x+10y+3z

g(x,y,z)=5x^2+5y^2+3z^2=43

We have to find the extreme values of the function.

f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3

g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z

\Delta f(x,y,z)=\lambda \Delta g(x,y,z)

Therefore,

10=\lambda 10x\implies x=\frac{1}{\lambda}

10=10y\lambda\implies y=\frac{1}{\lambda}

3=6z\lambda

z=\frac{1}{2\lambda}

Substitute the values in g(x)

Then, we get

\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43

\frac{20+20+3}{4\lambda^2}=43

\frac{43}{4\lambda^2}=43

\lambda^2=\frac{43}{4\times 43}

\lambda=\pm\frac{1}{2}

When \lambda=\frac{1}{2} then,

x=2,y=2,z=1

When \lambda=-\frac{1}{2}

Then, x=-2,y=-2,z=-1

f(2,2,1)=10+10+3=23

f(-2,-2,-1)=-10-10-3=-23

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0
4 years ago
Please help asap :(((
Alecsey [184]
You are right the answer is B
5 0
3 years ago
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A​ student's cost for last semester at her community college was ​$2000. She spent ​$280 of that on books. What percent of last​
Usimov [2.4K]

Answer:

14%

Step-by-step explanation:

A way I usually do it is with a fraction setup.

280/2000 = ?/100

multiply 280 by 100, and you get 28000. divide this by 2000, and you get 14!

8 0
3 years ago
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