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3 years ago

What are the zeros of the function f(x) = 10x2 + 9x + 2?

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

Answer:

x = -4/5 and -1/2

Step-by-step explanation:

"Finding zeroes" means find the x-values that make f(x) = 0, so we have...

0 = 10x² + 9x + 2

Use quadratic equation to solve...

x = [-9 ± √(9² - 4(10)(2))]/[2(10)]

x = [-9 ± √(81 - 80)]/20

x = [-9 ± √1]/20

x = [-9 ± 1]/20

x = (-9 + 1)/20 and (-9 - 1)/20

x = -8/20 and -10/20

x = -4/5 and -1/2

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Find [-4/5]×3/7×15/16×[-14/9]

dangina [55]

The given expression is $\frac{-4}{5} \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})$ .

We need to simplify the given expression.

<h3>What is a rational number?</h3>

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

Now group the rational numbers $(\frac{-4}{5}\times \frac{15}{16} ) \times (\frac{3}{7}\times (\frac{-14}{9}))$

$=(\frac{-4}{16}\times \frac{15}{5} ) \times (\frac{3}{9}\times (\frac{-14}{7}))$

$=(\frac{-1}{4}\times \frac{3}{1} ) \times (\frac{1}{3}\times (\frac{-2}{1}))$

$=(\frac{-3}{4} ) \times (\frac{-2}{3})=\frac{1}{2}$

Therefore, the simplified value of the given expression is $\frac{1}{2}$ .

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2 years ago

In ⊙P, QR≅ST. Which statement must be true? Select all that apply.

den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

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Given that the circle has a center P

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From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e. △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

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Divide

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2 years ago

Algebra Expression •x minus x

Tems11 [23]

The answer is 0.

The expression in algebraic form is :

x - x
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Step-by-step explanation:

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Two fewer than a number doubled is the same as the number decreased by 38. if n is "the number," which equation could be used to

Alona [7]

$\displaystyle \\ 
\text{We use the following equation:} \\ \\ 
 \frac{n}{2} = n - 38 \\ \\ 
We solve for n: \\ \\ 
 \frac{n}{2} = n - 38 ~~\Big| \times 2 \\ \\ 
n = 2 \times n - 2 \times 38 \\ \\ 
n = 2n - 76 \\ \\ 
2n - n = 76 \\ \\ 
\boxed{n = 76} \\ \\ 
\text{Verification: } \\ \\ 
\frac{n}{2} = n - 38 \\ \\ 
\frac{76}{2} = 76 - 38 \\ \\ 
\boxed{38 = 38 ~~~ Correct }$

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