What are the zeros of the function f(x) = 10x2 + 9x + 2?
1 answer:
Answer:
x = -4/5 and -1/2
Step-by-step explanation:
"Finding zeroes" means find the x-values that make f(x) = 0, so we have...
0 = 10x² + 9x + 2
Use quadratic equation to solve...
x = [-9 ± √(9² - 4(10)(2))]/[2(10)]
x = [-9 ± √(81 - 80)]/20
x = [-9 ± √1]/20
x = [-9 ± 1]/20
x = (-9 + 1)/20 and (-9 - 1)/20
x = -8/20 and -10/20
x = -4/5 and -1/2
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Answer:
the two points represent solutions to the equation 3x - 9y= 18
if y = 0,
3x - 9(0) = 18
3x = 18
x = 6
(6,0): point 1
if x = 9
3(9) - 9y = 18
27 - 9y = 18
-9y = -9
y = 1
(9, 1) : point 2
Step-by-step explanation:
It is a 9/4=2.25*2=4.5 Hope it helps :)
Answer: 285
Step-by-step explanation:
302 - 20 + 3
You see if the graphs passes the vertical line test. if any vertical line passes through more than one part of the graph then its not a function - just a relation.
We can write the equation 9x=4500 Now we just solve for x by dividing both sides by 9 to get: x=500 Hope this helps!