Question

Trapezoid DEFG is dilated by scale factor of 2\3 to form trapezoid D'E'FG. Side E'F' measures 32. What is the measure of side EF?

Answer 1

Answer: 48

Step-by-step explanation:

Given

Trapezoid DEFG is dilated by a scale factor of  $\frac{2}{3}$

$E'F'=32$

Suppose the length of EF is $x$

Multiply the side length of DEFG by $\frac{2}{3}$ to form E'F'

$\Rightarrow E'F'=x\times \dfrac{2}{3}\\\\\Rightarrow 32=x\times \dfrac{2}{3}\\\\\Rightarrow x=16\times 3\\\Rightarrow x=48$

$\therefore EF=48$