5 9/10+ 29/69+6 21/23

Which of these statements is true for f(x) = 4 . (7)*?

guajiro [1.7K]

Answer:

C. The y-intercept is (0, 4).

Step-by-step explanation:

The graph of f(x) = 4 is a straight line parallel to the x-axis passing through the point (0, 4).

6 0

3 years ago

A sum of Rs 1,50,000 amounts to Rs 2,62,500 at a

Naily [24]

Look at the attached picture⤴⤴

Hope this will help u....✔✔:)

3 0

3 years ago

When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr

marin [14]

Answer:

96.42% probability that the number of tails is between 40 and 60.

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

100 tosses, so $n = 100$

Two outcomes, both equally as likely. So $p = \frac{1}{2} = 0.5$

So

$E(X) = np = 100*0.5 = 50$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5$

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

$P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)$

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60.5 - 50}{5}$

$Z = 2.1$

$Z = 2.1$ has a pvalue of 0.9821

X = 39.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.5 - 50}{5}$

$Z = -2.1$

$Z = -2.1$ has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

8 0

3 years ago

An angle measuring 60 degrees is measured as 62 degrees. What is the percentage error correct to 3 significant figures?

Vadim26 [7]

Answer:

3.33%

Step-by-step explanation:

math stuuf <3

7 0

3 years ago

there are 22 roses, 12 daisies, and 16 carnations in a bouquet. what is the ratio of roses to the total number of flowers in the

Temka [501]

Given:
Roses: 22
Daisies: 12
Carnation: 16

22 + 12 + 16 = 50 flowers in one bouquet

The ratio of the roses to the total number of flowers in the bouquet is 22/50 or simplified to 11/25

Ratio of daisies to carnations is 12:16 or 3:4.

Number of carnations to add to make the ratio into 1:3

12:x = 1:3
12*3 = x
36 = x

36 - 16 = 20 additional carnations.

There must be an additional 20 carnations to make the ratio of daisies to carnation 1:3.

12:36 = 1:3

4 0

3 years ago