<span>To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. </span>
Given that the measure of ∠ADC = (7x + 2)° and arc AC = (8x - 8)°
We need to determine the measure of ∠ABC
<u>The value of x:</u>
The measure of ∠ADC can be determined using the formula,
![m\angle ADC=m \widehat{AC}](https://tex.z-dn.net/?f=m%5Cangle%20ADC%3Dm%20%5Cwidehat%7BAC%7D)
Substituting the values, we get;
![7x+2=8x-8](https://tex.z-dn.net/?f=7x%2B2%3D8x-8)
![-x+2=-8](https://tex.z-dn.net/?f=-x%2B2%3D-8)
![-x=-10](https://tex.z-dn.net/?f=-x%3D-10)
![x=10](https://tex.z-dn.net/?f=x%3D10)
Thus, the value of x is 10.
<u>The measure of ∠ADC:</u>
Substituting the value x = 10 in the measure of ∠ADC = (7x + 2)°
We have;
![\angle ADC=(7(10)+2)^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ADC%3D%287%2810%29%2B2%29%5E%7B%5Ccirc%7D)
![\angle ADC=(70+2)^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ADC%3D%2870%2B2%29%5E%7B%5Ccirc%7D)
![\angle ADC=72^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ADC%3D72%5E%7B%5Ccirc%7D)
Thus, the measure of ∠ADC is 72°
<u>The measure of ∠ABC:</u>
The measure of ∠ABC can be determined using the central angle theorem.
Thus, we have;
![\angle ADC=2\angle ABC](https://tex.z-dn.net/?f=%5Cangle%20ADC%3D2%5Cangle%20ABC)
![72^{\circ}=2\angle ABC](https://tex.z-dn.net/?f=72%5E%7B%5Ccirc%7D%3D2%5Cangle%20ABC)
![36^{\circ}=\angle ABC](https://tex.z-dn.net/?f=36%5E%7B%5Ccirc%7D%3D%5Cangle%20ABC)
Thus, the measure of ∠ABC is 36°
Hence, Option A is the correct answer.
Line them up as u see on the table
Answer:
Graph f(x)=1/4x-3. f(x)=14x−3 f ( x ) = 1 4 x - 3. Rewrite the function as an equation. y=x4−3 y = x 4 - 3. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps. ... Any line can be graphed using two points. Select two x ...
Step-by-step explanation:
The answer to the problem is A