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3 years ago

Tell whether the system has one solution, infinitely many solutions, or no solution. y=1/2x 2y-x=6

1 answer:

6 0

No solution.

2y-x=6 =y=1/2x+3
Since 1/2x does not equal 1/2x+3, this is a false statement and therefore has no solution

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Solve for v. 2 = 11 - 3v v=

Sveta_85 [38]

Answer:

The answer would be V=3

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3 years ago

What is 7.8 x 10^5 hours in days?

dimaraw [331]

3.250 x 10^4, will be the correct answer.

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3 years ago

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You get your hair done for $56.00 and you tip the hairdresser 20%. How much is your tip?

suter [353]

You get your hair done for $56.00 and you tip the hairdresser $20.00(D)

You have to subtract 56 from 20% than round the answer to the neared tenth.

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3 years ago

Christine buys 7 hamburgers and 3 sodas for $27.95. Laura buys 5 hamburgers and 4 sodas for $23.40. How much does a hamburger co

Naddika [18.5K]

7h+3s=27.95 subtract 7h from both sides

3s=27.95-7h divide both sides by 3

s=(27.95-7h)/3

Then we are told:

5h+4s=23.4, using s found above makes this equation become:

5h+4(27.95-7h)/3=23.4 multiply both sides by 3

15h+4(27.95-7h=70.2 perform indicated multiplication on left side

15h+111.8-28h=70.2 combine like terms on left side

-13h+111.8=70.2 subtract 111.8 from both sides

-13h=-41.6 divide both sides by -13

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3 years ago

A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th

myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

$h+c=593\\c=h-57$

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

$h+h-57=593\\2h-57=593\\2h=650\\h=325$

Therefore, the number of hamburgers sold on Thursday were 325.

6 0

3 years ago