2 years ago

2 Solve for x L (1 Point) 3x + 25 = 38

Mathematics

1 answer:

il63 [147K]2 years ago

4 0

Answer:

X = 13/3

Step-by-step explanation:

3x + 25 = 38

3x = 13

x = 13/3

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If you take a number, times by 7 then subtract 1. You get the same as if you took the number multiply the number by 5 then subtr

Irina-Kira [14]

Answer:

-7/2 or -3.5

Step-by-step explanation:

Make the equation first

7x-1 = 5x-8

7 = -2x

-7/2 = x

4 0

2 years ago

Read 2 more answers

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$