How does the length of the hypotenuse ina right triangle relate to the lengths of the legs?

Segment AB has endpoints at A(-7,2) and b(9,-6). Point P lies on AB such that AP:BP=3:1

bekas [8.4K]

The coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is (x,y) = (5,-4)

<h3>What is the coordinate of the point which divides a line segment in a specified ratio?</h3>

Suppose that there is a line segment $\overline{AB}$ such that a point P(x,y) lying on that line segment $\overline{AB}$ divides the line segment $\overline{AB}$ in m:n, then, the coordinates of the point P is given by:

$(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)$

where we have:

the coordinate of A is $(x_1, y_1)$
and the coordinate of B is $(x_2, y_2)$

We're given that:

Coordinate of A is $(x_1, y_1)$ = (-7,2)
Coordinate of B is $(x_2, y_2)$ = (9.-6)
The point P lies on AB such that AP:BP=3:1 (so m = 3, and n = 1)

Let the coordinate of P be (x,y), then we get the values of x and y as:

$(x,y) = \left( \dfrac{mx_2 + nx_1}{m+n} , \dfrac{my_2 + ny_1}{m+n} \right)\\\\(x,y) = \left( \dfrac{3(9) + 1(-7)}{3+1} , \dfrac{3(-6) + 1(2)}{3+1} \right)\\\\(x,y) = \left( \dfrac{20}{4} , \dfrac{-16}{4} \right) = (5,-4)$

Thus, the coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is (x,y) = (5,-4)

Learn more about a point dividing a line segment in a ratio here:

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4 0

2 years ago

What is the length of a dresser

NeX [460]

The answer is 35 inches.

8 0

3 years ago

Read 2 more answers

The coordinates of AB are A(-5, -1) and B(-2, -6). If AC : CB = 3 : 7, what are the coordinates of point C?

navik [9.2K]

$\text{Let the coordinates of AB are }A(-5,-1), \text{ and }B(-2, -6)\\
\\
\text{let the coordinate of th point C be (x, y), such that}\\
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AC:CB=3:7\\
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\text{By the section formula, we know that if P(x,y) lies on a line segment AB}\\
\text{where, }A(x_1,y_1), \ B(x_2,y_2)\text{ and satisfy the ratio, }AP:PB=m:n, \text{ then}$

$P=\left ( \frac{mx_2+nx_1}{m+n}, \ \frac{my_2+ny_1}{m+n} \right ).\\
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\text{So using this formula, we get for the given problem}\\
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C=\left ( \frac{3(-2)+7(-5)}{3+7}, \ \frac{3(-6)+7(-1)}{3+7} \right )\\
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\Rightarrow C=\left ( \frac{-6-35}{10}, \ \frac{-18-7}{10} \right )\\
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\Rightarrow C=\left ( \frac{-41}{10}, \ \frac{-25}{10} \right )\\
\\
\Rightarrow C=\left ( -4.1, \ -2.5 \right )$

Coordinates of the point C is: (-4.1, -2.5)

5 0

3 years ago

Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

As we go from (–2, 2) to (3, 4), x increases by 5 and y increases by 4. Thus, the slope of the line through (–2, 2) and (3, 4) is

m = rise / run = 4/5.

Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b. Multiplying all three terms by 5, we eliminate the fraction: 20 = 12 + b. Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

A line parallel to this one would have the form y = (4/5)x + b; note that the slopes of these two lines are the same, but the y-intercept, b, would be different if the two lines do not coincide.

Unfortunately, you have not shared the ordered pairs given in this problem statement.

You could arbitrarily let b = 0. Then the parallel line has equation

y = (4/5)x; if x = 3, then y = (4/5)(3) = 12/5, and so (3, 12/5) lies on the parallel line.

3 0

2 years ago

Read 2 more answers

Which of the following is a foci of x^2/16-y^2/4=1

kolbaska11 [484]

Answer:

x(8;2)

Step-by-step explanation:

i think that

3 0

2 years ago