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WARRIOR [948]
3 years ago
13

Jack works for a company that pays him $20 an hour. His normal workday does not exceed 8 hours. After working 8 hours in a day,

he gets paid $5 per hour overtime in addition to his regular wage. He cannot work fewer than 5 hours a day or more than 14 hours a day. Which graph shows Jack's wages if he works for x hours a day?
Mathematics
1 answer:
trapecia [35]3 years ago
3 0
It would have a domain of between 5 and 14 and a range of 100$ to 310$
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Explain the following composite numbers into product of prime factors.<br>5929​
Alexxx [7]
Since, the prime factors of 5929 are 7, 11. Therefore, the product of prime factors = 7 × 11 = 77.
7 0
2 years ago
Which of the following are solutions to the equation below? Check all that apply. 9x^2-64=0
nikdorinn [45]

Answer:

E. -8/3

F. 8/3

Step-by-step explanation:

9x^2-64=0

Add 64 to each side

9x^2-64+64 = 0+64

9x^2 =64

Divide each side by 9

9x^2/9 = 64/9

x^2 = 64/9

Take the square root of each side

sqrt(x^2) = ±sqrt(64/9)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

x = ±sqrt(64)/sqrt(9)

x = ± 8/3

4 0
3 years ago
The quotient of a number and 5, less 10, is 3
sergejj [24]
Quotient is the result of division. Assign a variable to the unknown number. Let's make it x. Write the statement as an equation.
x/5 - 10 = 3

solve for x

x/5 - 10 = 3
x/5 = 3 + 10
x/5 = 13
x = 5 × 13
x = 65 

4 0
3 years ago
A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are
kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = ^nC_r=\dfrac{n!}{r!(n-r)!}

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15

Hence , the number of different combinations of 2 vegetables are possible = 15 .

5 0
3 years ago
What is b in terms of a and c?
aev [14]

Answer:

b=\sqrt{c^2-a^2}

Step-by-step explanation:

The given relation is

c=\sqrt{a^2+b^2}

To make b the subject, we square both sides of the equation to get;

c^2=(\sqrt{a^2+b^2})^2

c^2=a^2+b^2

Isolate b on one side of the equation;

c^2-a^2=b^2

Or

b^2=c^2-a^2

We take the positive square root of both sides to get;

b=\sqrt{c^2-a^2}

6 0
3 years ago
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