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Tanzania [10]
4 years ago
5

Of the 1640 students in rolled at school 50% come to school by bus 35% come by car and the rest of the students walk to school h

ow many students of the school
Mathematics
1 answer:
Eva8 [605]4 years ago
8 0

Answer:

256

Step-by-step explanation:The total amount os students is 1640 which is equivalent to 100% so we get 50% of 1640 which is equall to 820 students after that we also find 35% of 1640 which is equall to 564 students. After that we sum them up which we get 1384 students and subtract it from 1640 and get 256 students.


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Cos(a) 63/65 to find sin(a) and tan(a)
Semenov [28]

Answer:

\huge\boxed{\sin\alpha=-\dfrac{16}{65},\ \tan\alpha=-\dfrac{16}{63}}\\\\or\\\\\huge\boxed{\sin\alpha=\dfrac{16}{65},\ \tan\alpha=\dfrac{16}{63}}

Step-by-step explanation:

\cos\alpha=\dfrac{63}{65}\\\\\text{use}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\alpha+\left(\dfrac{63}{65}\right)^2=1\\\\\sin^2\alpha+\dfrac{3969}{4225}=1\qquad\text{subtract}\ \dfrac{3969}{4225}\ \text{from both sides}\\\\\sin^2\alpha=\dfrac{4225}{4225}-\dfrac{3969}{4225}\\\\\sin^2\alpha=\dfrac{256}{4225}\to\sin\alpha=\pm\sqrt{\dfrac{256}{4225}}\\\\\sin\alpha=\pm\dfrac{\sqrt{256}}{\sqrt{4225}}\\\\\sin\alpha=\pm\dfrac{16}{65}

\text{use}\ \tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}\\\\\text{substitute:}\\\\\tan\alpha=\dfrac{\pm\frac{16}{65}}{\frac{63}{65}}=\pm\dfrac{16}{65}\cdot\dfrac{65}{63}=\pm\dfrac{16}{63}

3 0
4 years ago
Read 2 more answers
What is the value of 6\7 = ?
Sergio039 [100]
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Degree 3 polynomial with zeros -7, 3i, and -3i
d1i1m1o1n [39]

A polynomial having degree 3 with zeros -7, 3i, and -3i is:
x³+ 7x² - 9x - 63

The correct answer is an option (A)

In this question, we need to find the polynomial whose degree is 3 polynomial and zeros are -7, 3i, and -3i

The zeros of the required polynomial = -7, 3i, and -3i

This means, the roots of the polynomial = (x + 7), (x - 3i) and (x + 3i)

We know that in complex numbers, i = √-1

So, 3i = 3√-1

          = √-9

i.e., the roots of the polynomial are (x + 7), (x - √-9) and (x + √-9)

And the polynomial would be,

(x + 7)(x - √-9)(x + √-9)

= (x + 7)(x² - (√-9)²)

= (x + 7)(x² - (-9))

= (x + 7)(x² + 9)

=  x³+ 7x² - 9x - 63

Therefore, a polynomial having degree 3 with zeros -7, 3i, and -3i is:
x³+ 7x² - 9x - 63

The correct answer is an option (A)

Learn more about the polynomial here:

brainly.com/question/14344049

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4 0
1 year ago
What are the effects of different operations on rational and irrational numbers?
lara31 [8.8K]

Answer:

An irrational number is a number that is not rational that means it is a number that cannot be written in the form  

p

q

. An irrational Number is a number on the Real number line that cannot be written as the ratio of two integers. They cannot be expressed as terminating or repeating decimals. For example.

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√3 = 1.732050807. So one of the most important thing about irrational numbers is that it never repeats and never terminates.

Step-by-step explanation:

6 0
3 years ago
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