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Considering the function for the remaining amount of cesium in the atmosphere, F(x) = 1000×0.5^(x/30), we have;
First part:
- The area will be safe again in about 100 years time.
Second part;
- The y-intercept is at the start of the measurement
Third part;
- The function is a decay function
<h3>Which method can be used to evaluate the given function?</h3>
First part;
The given function for the remaining amount of cesium is presented as follows;

When 100 kg. of cesium is remaining, we have;

Which gives;


- Therefore, the area will be safe again in approximately 100 years.
Second part;
The y-intercept is given by the point where <em>x </em>= 0
At the y-intercept, we therefore have;

At the y-intercept, the amount of cesium remaining, F(x) is 1,000, which is the initial amount of cesium.
- The y-intercept is therefore, at the start of the measurement, where 1000 kg. is present in the atmosphere.
Third part;
The amount of cesium remaining F (x) decreases as the time, <em>x</em>, increases, the function is therefore a decay function.
Learn more about exponential functions here;
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Answer:
cot(θ) = 4/5
Step-by-step explanation:
In the polar/rectangular coordinate representation (x, y) ⇔ (r; θ), we know that ...
(x, y) = (r·cos(θ), r·sin(θ))
From the various trig definitions and identities, we also know that ...
cot(θ) = cos(θ)/sin(θ) = (x/r)/(y/r) = x/y
For the given (x, y) = (-4, -5), the cotangent is ...
cot(θ) = -4/-5 = 4/5
Answer: The ladder is sliding down the wall at a rate of 
Step-by-step explanation:
Since we have given that
Length of ladder = 25 foot
Distance from the wall to the bottom of ladder = 15 feet
Let base be 'x'.
Let length of wall be 'y'.
So, by pythagorus theorem, we get that


Now, the equation would be

Differentiating w.r.t x, we get that

Hence, the ladder is sliding down the wall at a rate of 
Put the numbers in the given equation and solve for k.
... $11 = k·(8 €)
Divide by the coefficient of k:
... k = $11/(8 €) = 1.375 $/€
Then your equation is ...
... y = (1.375 $/€)x
_____
It is fairly common to leave the units out of such equations, assuming that everyone understands that x is in euros and y is in dollars and the conversion factor includes a unit change from euros to dollars. Thus, you might expect to see ...
... y = 1.375·x