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Aloiza [94]
3 years ago
10

The distance, in feet, two boys travel per second on a treadmill is shown to the left. which comparison is accurate? A. Xavier i

s traveling at 1.5 feet per second.
B. Moises is going faster than Xavier
C. The difference in their rates of change is 1 foot per second.
D. If both boys remain in the treadmill for 10 minutes, Xavier will have traveled a greater distance.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0

Xavier:

15/2 = 7.5 feet/s

Moises:

5/1 = 5 feet/s


Therefore, A is incorrect, B is incorrect and C is incorrect, so the answer is D

rusak2 [61]3 years ago
5 0

Answer:

Rates of change from Xavier is bigger then rates of change from Moises

Vx > Vm

Step-by-step explanation:

From this graph we can calculate the velocity ( which is rates of change) or feet per second

Velocity of Xavier is:

Vx = 15 / 2 = 7.5 ft/sec

Velocity of Moises is:

Vm = 15 / 3 = 5 ft/sec

We can see that velocity Vx is bigger than Vm, which means that

Vx > Vm

God with you!!!

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