4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b
Answer:
4sqrt(2) cm
Step-by-step explanation:
a^2 + b^2 = c^2
4^2 + 4^2 = c^2
32 = c^2
sqrt(32) = c
c = 4sqrt(2)
Answer:
62 units
Step-by-step explanation:
The absolute value of a number A is the positive distance between 0 and the number A (you can think this distance as the distance measured with a ruler from 0 to the number). For example:
|-2|=2 , |25|=25, |-3|=3, |-25.3|=25.3
Note that the absolte value is always positive.
The distance between two numbers P,Q in the real line is the absolute value of the difference between the two points:
Hence, the distnce between P=-50 and Q=12 is equal to
Y/6 - 5 = 2. First add 5 to both sides. Then multiply both sides by 6. The answer to y is 42. To check plug in 42 for y. 42/6 -5 = 2 ==> 7-5 = 2 ===> 2=2. Therefore it is correct. ANSWER: y=42.
I believe the answer would be 6.
Please mark as brainliest!
