4 years ago

Solve the following inequality for x (nearest tenth): -4<-17.03-7x

Mathematics

1 answer:

Mila [183]4 years ago

8 0

Answer:

x<-1303/700

Step-by-step explanation:

You might be interested in

Simplify the expression. (3x2 – 4x + 1) + (-x2 + x – 9)

LuckyWell [14K]

$(3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8$

4 0

4 years ago

Read 2 more answers

An aircraft has a total time in service of 468 hours. The Airworthiness Directive given was initially complied with at 454 hours

Georgia [21]

Answer:

440 hours

Step-by-step explanation:

In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:

Hours of the second cycle= Total time in service- time Airworthiness Directive

=468-454=14

Then we have 14 hours of service and need to accumulate the rest to complete 454. It is

454-14=440

Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .

6 0

3 years ago

HURRY!!!!!!!!!<br><br> Given P(5,10,8) and Q(7,11,10), find the midpoint of the segment PQ.

rusak2 [61]

Answer:

$P_{m}=(6,10.5,9)$

Step-by-step explanation:

The mid point can be found with the formula

$P_{m}=(\frac{x_{1}+x_{2} }{2},\frac{y_{1} +y_{2} }{2} ,\frac{z_{1}+z_{2} }{2} )$

The given coordinates are $P(5,10,8)$ and $Q(7,11,10)$ .

Replacing coordinates in the formula, we have

$P_{m}=(\frac{5+7}{2},\frac{10+11 }{2} ,\frac{8+10}{2} )=(\frac{12}{2},\frac{21 }{2} ,\frac{18}{2} )\\P_{m}=(6,10.5,9)$

Therefore, the mid point of the segment PQ is $P_{m}=(6,10.5,9)$

4 0

4 years ago

6. A number solid with faces labeled 1 through 16 is rolled. What is the probability that the number 16 will appear facing up wh

erma4kov [3.2K]

Answer:

1/16 chance that it will land on 16 because there are 16 faces

6 0

3 years ago

Read 2 more answers

Help with this question please help

levacccp [35]

Slope is 2
Y intercept is 4

8 0

3 years ago