Answer:
- Code is in JAVA language. As there is no user input the logic is straightforward.
- Below is the code along with a detailed explanation of the logic.
- The class name is Print main save as file as the main class.
Explanation:
Program:-
public class Main{
public static void main(String args[]){
/* There are two for loops...
* First for loop runs from i=1 to i=9
* Second for loop runs from j=1 to j=i.
*
*/
for(int i=1;i<=9;i++){
for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i
/*Prints I and j next to each other*/
System.out.println(i+""+j);
}//for loop of j ends here
}// for loop of I ends here
}
}
Answer:
A
Explanation:
This Information involves informing the young youth about adult and mature life
Charles baggage (picture for more info)
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}