Answer:
The area would be 40.5 cm ^2
Step-by-step explanation:
Well first you don’t gotta worry about some isosceles trapezoid thingy.
You just gotta know the formula for a trapezoid is (b1+b2)/2)h
B1 in this case is or base 1 (9 or 4.5)
b2 in this case is or base 2 (9 or 4.5)
(you can only choose one base for each)
ANd you add those 2 up and you’d get 13.5
13.5/2 which is 6.75
Now we multiply it by the height which is 6 and gte 40.5
40.5cm ^2 is the final answer
Answer:
z+11y/5 = x
Step-by-step explanation:
Since you are solving for x, you want to isolate the variable. You do that by adding 11y to both sides, which cancels out the -11y. From that you should have z+11y = 5x. To cancel out the 5x you need to divide both sides by 5 to get z+11y/5 = x. Hope this helps :)
Answer:
x=6
Step-by-step explanation:
The inverse is the equation with the x and y variables transposed
Answer: ![\sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125x%5E3%7D)
.
Step-by-step explanation: Given radical expression
![\sqrt[3]{5x} \times \sqrt[3]{25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D)
.
According to the product property of roots.
![\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%20%5Ctimes%20b%7D)
On applying above rule, we get
![\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B25x%5E2%7D%20%3D%20%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D)
5 × 25 = 125 and
Therefore,
![\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5x%20%5Ctimes%2025x%5E2%7D%3D%20%5Csqrt%5B3%5D%7B125x%5E3%7D)
<h3>So, the correct option would be second option
.</h3>
Answer: X = 3t, Y =2 - t, Z =2
Step-by-step explanation: the plane
x + y + z =4has normal vector
M =<1,1,1> and the line
x = 1 + t, y = 2 − t, z = 2t has direction
v =<1, −1, 2>. So the vector
A= n × v
=<1, 1, 1> × <1, −1, 2>
=<2−(−1),1−2,−1−1>
=<3,−1,−2>
