You have to solve for y
Subtract 2x to the other side
Divide both sides by 4
y=-1x/2-2
Graph D has a slope of -1/2 and a y-intercept of -2
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
From this picture you can calculate coordinates of triangles' vertices:
.
Since
you can conclude that points A, B, C are rotated by
about the point (-0.5,0) to form points J, G, H, respectively.
Answer: A is correct choice.
Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had
Answer:
35°
Step-by-step explanation:
We assume that points S, T, U, V all lie on the circle.
Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.
Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.
Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:
∠VSU = 70°/2
∠VSU = 35°
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