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bonufazy [111]
3 years ago
12

50. At a booth at the school carnival in past years, they've found that 32% of students win a stuffed toy ($3.25), 10% of studen

ts win a jumprope ($1.70), and 8% of students win a t-shirt ($7.80). The remaining students do not win a prize. If 200 students play the game at the booth, how much money should the carnival committee expect to pay for prizes for that booth
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

The expected amount to be paid by the carnival committee for prices would be $366.80

Step-by-step explanation:

Hello!

Here, we want to calculate the amount of money the carnival committee is expected to pay for the prizes for that booth

From the question, we have 3 categories of prices to be won

To calculate for people that won’t win anything , we simply subtract the percentages of all from 100

That would be 100-32-10-8 = 100-50 = 50%

So now let’s calculate the number of people out of 200 that will win each category based on the percentages

For stuffed toy

32/100 * 200 = 64

Jump rope

10/100 * 200 = 20

For t-shirt

8/100 * 200 = 16

So total price paid for stuffed toy= 3.25 * 64 = $208

For jump rope, we have 1.7 * 20 = $34

For t-shirt , we hav 16 * 7.8 = $124.8

So the total value spent on prices by the committee would be;

124.8 + 34 + 208 = $366.80

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