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MAVERICK [17]
3 years ago
7

Write prime factorizations of the number 18.

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

18 is a composite number. 18 = 1 x 18, 2 x 9, or 3 x 6. Factors of 18: 1, 2, 3, 6, 9, 18.

Prime factorization: 18 = 2 x 3 x 3, which can also be written 18 = 2 x 3²

<em>hope the answer helped:)</em>

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luda_lava [24]

Answer:

600 sq in

Step-by-step explanation:

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3 years ago
The number of new visits to a website is decreasing exponentially. It can be modeled by the function h(d)=2170(0.92)^d, where h
In-s [12.5K]

Answer:

2) -141 hits/da  

Step-by-step explanation:

Calculate the values of h(2) and h(4)

h(2) = 2170(0.92)² = 2170 × 0.8464 = 1837

h(4) = 2170(0.92)⁴ = 2170 × 0.7164 = 1555

Calculate the average rate of change

Rate of change = (y₂ - y₁)/(x₂-x₁) = (1555 -1837)/(4 - 2) = -282/2 = -141 hits/da

The average rate of change is -141 hits/da.

In the figure below, the red curve represents the function h(d), while the green dashed line represents the average rate of change over the interval 2 ≤ d ≤4.

8 0
3 years ago
Find the percent of change, original: $75 new: $60
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80%

Step-by-step explanation:

60/75 = 4/5 = 0.80

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6 0
3 years ago
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How is simplifying similar to division?
Alex
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4 years ago
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A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

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6 0
3 years ago
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