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Gemiola [76]
3 years ago
12

A mixture may be composed of elements, compounds or both. True False

Chemistry
1 answer:
AveGali [126]3 years ago
4 0

Answer:

True

Explanation:

A mixture is usually categorised as an impure substance in chemistry. It has the following properties:

  • It's composition is indefinite. It can be made up of any proportion of elements or compounds or both.
  • The constituent retains their identites i.e they do not chemically combine.
  • Mixtures are easily seperated by physical methods.
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A gaseous compound containing carbon and hydrogen was analyzed and found to consist of 83.65% carbon by mass. The molar mass of
steposvetlana [31]

Answer:

The molecular formula is C6H14

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

A compound contains:

Carbon = 83.65 % = 83.65 grams

Hydrogen = 16.35 % = 16.35 grams

Atomic mass of carbon = 12.01 g/mol

Atomic mass of hydrogen = 1.01 g/mol

Molar mass of compound = 86.2 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles carbon = 83.65 grams / 12.01 g/mol

Moles carbon = 6.965 moles

Moles hydrogen = 16.35 grams / 1.01 g/mol

Moles hydrogen = 16.19 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 6.965 moles / 6.965 moles = 1

H = 16.19 moles / 6.965 moles = 2.33

This means for 1 mol C we have 2.33 moles H  OR for 3 moles C we have 7 moles H

The empirical formula is C3H7

The molecular mass of this formula is 43.1 g/mol

Step 4: Calculate molecular formula

We have to multiply the empirical formula by n

n = 86.2 g/mol / 43.1 g/mol

n = 2

Molecular formula = 2*(C3H7) = C6H14

The molecular formula is C6H14

7 0
4 years ago
What is the molar mass for MgO?
podryga [215]

Answer:

40.3044 g/mol

Explanation:

4 0
3 years ago
Four gases were combined in a gas cylinder with these partial pressures: 3. 5 atm N2, 2. 8 atm O2, 0. 25 atm Ar, and 0. 15 atm H
aksik [14]

The total pressure of the gas has been 11.9 atm.

The partial pressure has been the pressure exerted by the individual gas in the mixture.

According to the Dalton's law of Partial pressure, the pressure of the gas has been the sum of the partial pressure of each gas in the mixture.

<h3 /><h3>Computation for the pressure of gas</h3>

The given gas has partial pressure of Nitrogen, P_{N_2}=3.5\;\rm atm

The partial pressure of Oxygen, P_{O_2}=8\;\rm atm

The partial pressure of Argon, P_{Ar}=0.25\;\rm atm

The partial pressure of Helium, P_{He}=0.15\;\rm atm

The total pressure, (<em>P</em>) of the gas has been given as:

P=P_{N_2}\;+\;P_{O_2}\;+\;P_{Ar}\;+\;P_{He}\\&#10;P=3.5\;+8\;+\;0.25\;+\;0.15\;\text{atm}\\&#10;P=11.9\;\rm atm

The total pressure of the gas has been 11.9 atm.

Learn more about the vapor pressure, here:

brainly.com/question/25356241

7 0
3 years ago
PLEASE HELP
n200080 [17]
Mk i will comment so u can make them brainliest lols
6 0
3 years ago
Read 2 more answers
The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compoun
GarryVolchara [31]

K_{sp} of the compound is found to be  5.04 ×10^{-10}.

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [A^{+} ]^{a} [B^{-} ]^{b}

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × 10^{-2} g/L

molar mass = 288 g/ mol

∴ s= 3.60 × 10^{-2} g/L ÷ 288 g/ mol = 1.25 ×10^{-4} mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

K_{sp} =[ M^{+3}] [ X^{-1}]^{3} = solubility product

∴ K_{sp} =[s]^{} [3s]^{3}

∴ K_{sp} = 3 s^{4}

∴ K_{sp} = 3 × (3.60 × 10^{-2} )^{4}

∴ K_{sp} = 503.8848 ×10^{-8}  = 5.04 ×10^{-10}

Learn more about solubility here .....

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7 0
2 years ago
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