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lana [24]
3 years ago
6

What is the molar mass for MgO?

Chemistry
1 answer:
podryga [215]3 years ago
4 0

Answer:

40.3044 g/mol

Explanation:

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Select the two variables that are held constant when testing Boyle's law in a manometer.
MrRissso [65]
Start studying Pressure - Volume Relationships in Gases (Boyle's Law). Learn vocabulary, terms ...Select<span> all that apply. V2 = k/P2 V2 = P1V1/P2 ... What </span>two variables<span> are </span>held constant when testing Boyle's Law in a manometer<span>? Temperature hope this helps

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3 years ago
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The final marks in a statistics course are normally distributed with a mean of 70 and a standard deviation of 10. The professor
Alinara [238K]
Use inversenormal on a calculator and type in .1 , 70 , 10 . That percent is for A and will determine at what mark an A will be. Do the same for the rest of the grades but change the first argument in the calculation
6 0
3 years ago
Blast furnaces extract pure iron from the iron(III) oxide in iron ore in a two step sequence.In the first step, carbon and oxyge
Alona [7]

Answer:

The net chemical equation for the production of iron from carbon, oxygen and iron(III) oxide:

2Fe_2O_3 (s) +6C (s) + 3O_2 (g)\rightarrow 4Fe (s) + 6CO_2 (g)

Explanation:

Step 1: Carbon and oxygen react to form carbon monoxide:

2C (s) + O_2 (g)\rightarrow 2CO (g)..[1]

Step 2: Iron(III) oxide and carbon monoxide react to form iron and carbon dioxide:

Fe_2O_3 (s) + 3CO (g)\rightarrow 2Fe (s) + 3CO_2 (g)..[2]

The net chemical equation for the production of iron from carbon, oxygen and iron(III) oxide can be obtained by :

3 × [1] + 2 × [2]

2Fe_2O_3 (s) + 6CO (g)+6C (s) + 3O_2 (g)\rightarrow 4Fe (s) + 6CO_2 (g)+6CO(g)

CO gas will gas cancel out form both sides ans we will get the net chemical equation:

2Fe_2O_3 (s) +6C (s) + 3O_2 (g)\rightarrow 4Fe (s) + 6CO_2 (g)

According to reaction, 2 moles of ferric oxide reacts with 6 moles of carbon and 3 moles of oxygen gas to give 4 moles of iron and 6 moles pf carbon dioxide gas.

8 0
4 years ago
What is this chemical component? thanks!!!
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It's just H20 but with 3 water molecules

8 0
3 years ago
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What is the molarity of a solution composed of 4.73 g of potassium iodide (KI) dissolved in enough water to make 0.169 L of solu
Kazeer [188]

Answer:

[KI] = 0.17 M

Explanation:

We determine the moles of solute:

Mass / Molar mass → 4.73 g / 166 g/mol = 0.0285 moles

Molarity (mol/L) is defined as moles of solute in 1L of solution

It is a sort of concentration

M = 0.0285 mol / 0.169L = 0.17 M

Instead of making the division (mol/L), we can also try this rule of three:

In 0.169 L we have 0.0285 moles of solute

in 1 L we must have ___ (1 . 0.0285) / 0.169 = 0.17 mol/L

4 0
3 years ago
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