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RideAnS [48]
4 years ago
5

A gaseous compound containing carbon and hydrogen was analyzed and found to consist of 83.65% carbon by mass. The molar mass of

the compound is 86.2 g/mol. What is the molecular formula of the compound
Chemistry
1 answer:
steposvetlana [31]4 years ago
7 0

Answer:

The molecular formula is C6H14

Explanation:

Step 1: Data given

Suppose the mass of compound = 100 grams

A compound contains:

Carbon = 83.65 % = 83.65 grams

Hydrogen = 16.35 % = 16.35 grams

Atomic mass of carbon = 12.01 g/mol

Atomic mass of hydrogen = 1.01 g/mol

Molar mass of compound = 86.2 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles carbon = 83.65 grams / 12.01 g/mol

Moles carbon = 6.965 moles

Moles hydrogen = 16.35 grams / 1.01 g/mol

Moles hydrogen = 16.19 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 6.965 moles / 6.965 moles = 1

H = 16.19 moles / 6.965 moles = 2.33

This means for 1 mol C we have 2.33 moles H  OR for 3 moles C we have 7 moles H

The empirical formula is C3H7

The molecular mass of this formula is 43.1 g/mol

Step 4: Calculate molecular formula

We have to multiply the empirical formula by n

n = 86.2 g/mol / 43.1 g/mol

n = 2

Molecular formula = 2*(C3H7) = C6H14

The molecular formula is C6H14

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Anika [276]
Carbon 13 I believe.
Never heard of an isotope for boron or nitrogen and I know Carbon 12 is the original form of carbon so.. Yeah
5 0
4 years ago
Determine the density of nh3 gas at 435k and 1.00atm
goldenfox [79]
We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

PV=nRT 

We manipulate this equation to give us an expression which will correspond to density. We do as follows:

PV= nRT
P/RT = n/V where n = m/MM
P(MM) /RT = m/V = density
Density = 1.00 (17.03) / 0.08206 (435)
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5 0
4 years ago
I NEED THIS NOW PLEASE HELP ​
ad-work [718]

Answer:

photosynthesis

Explanation:

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3 0
4 years ago
The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0
4 years ago
A person walks north for 5 miles, then south for 8 miles, and then north for 6 more miles. The entire trip takes 8 hours.
Zinaida [17]

Answer:

I am not sure

Explanation:

5 0
3 years ago
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