Which sample of matter is a mixture?

NeTakaya

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6 0

3 years ago

1) A certain compound has an empirical formula of CH_6O_ 2. Its molar mass is between 285 and 315 g/mol. What is its molecular f

KIM [24]

1. The molecular formula of the compound is C₆H₃₆O₁₂

2. The molecular formula of the compound is N₂H₄O₂

3 The empirical formula and molecular formula of the compound are: C₂H₃ and C₄H₆

4. The empirical formula of the compound is C₃H₆O

5. The empirical formula of the compound is ZrSiO₄

<h3>1. How to determine the molecular formula </h3>

Empirical formula = CH₆O₂
Molar mass = (285 + 315) / 2 = 600 / 2 = 300 g/mole
Molecular formula =?

Molecular formula = empirical × n = molar mass

[CH₆O₂]ₙ = 300

[12 + (6×1) + (16×2)]ₙ = 300

50n = 300

Divide both side by 74

n = 300 / 50

n = 6

Molecular formula = [CH₆O₂]ₙ

Molecular formula = [CH₆O₂]₆

Molecular formula = C₆H₃₆O₁₂

<h3>2. How to determine the molecular formula </h3>

Empirical formula = NH₂O
Molar mass = (55 + 65) / 2 = 120 / 2 = 60 g/mole
Molecular formula =?

Molecular formula = empirical × n = molar mass

[NH₂O]ₙ = 60

[14 + (2×1) + 16]ₙ = 60

32n = 60

Divide both side by 32

n = 60 / 32

n = 2

Molecular formula = [NH₂O]ₙ

Molecular formula = [NH₂O]₂

Molecular formula = N₂H₄O₂

<h3>3. How to determine the empirical formula and molecular formula</h3>

We'll begin by obtaining the empirical formula. This is illustrated below:

Carbon (C) = 88.9%
Hydrogen (H) = 11.1%
Empirical formula =?

Divide by their molar mass

C = 88.9 / 12 = 7.4

H = 11.1 / 1 = 11.1

Divide by the smallest

C = 7.4 / 7.4 = 1

H = 11.1 / 7.4 = 3/2

Multiply by 2 to express in whole number

C = 1 × 2 = 2

H = 3/2 × 2 = 3

Thus, the empirical formula of the compound is C₂H₃

Finally, we shall determine the molecular formula of the compound. This is illustrated below:

Molar mass of compound = 54 g/mol
Empirical formula = C₂H₃
Molecular formula =?

Molecular formula = empirical × n = molar mass

[C₂H₃]ₙ = 75.16

[(12×2) + (3×1)]ₙ = 54

27n = 54

Divide both side by 27

n = 54 / 27

n = 2

Molecular formula = [C₂H₃]ₙ

Molecular formula = [C₂H₃]₂

Molecular formula = C₄H₆

<h3>4. How to determine the empirical formula</h3>

Carbon (C) = 62.07%
Hydrogen (H) = 10.34%
Oxygen (O) = 27.59%
Empirical formula =?

Divide by their molar mass

C = 62.07 / 12 = 5.1725

H = 10.34 / 1 = 10.34

O = 27.59 / 16 = 1.724

Divide by the smallest

C = 5.1725 / 1.724 = 3

H = 10.34 / 1.724 = 6

O = 1.724 / 1.724 = 1

Thus, the empirical formula of the compound is C₃H₆O

<h3>5. How to determine the empirical formula</h3>

Zr = 49.76%
Si = 15.32%
O = 34.91%
Empirical formula =?

Divide by their molar mass

Zr = 49.76 / 91 = 0.547

Si = 15.32 / 28 = 0.547

O = 34.91 / 16 = 2.182

Divide by the smallest

Zr = 0.547 / 0.547 = 1

Si = 0.547 / 0.547 = 1

O = 2.182 / 0.547 = 4

Thus, the empirical formula of the compound is ZrSiO₄

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7 0

2 years ago

A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant

lakkis [162]

We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
$\frac{V1}{T1} = \frac{V2}{T2}$
In our case:
$\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \ T2= \frac{2.50*36.00}{2.00} = 45$

6 0

4 years ago

Read 2 more answers

A sample of Br 2 ( g ) Br2(g) takes 42.0 min 42.0 min to effuse through a membrane. How long would it take the same number of mo

Simora [160]

15 mins

~Savannah

Jokes from Savannah~

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The man goes home, sees his wife in the kitchen, cutting carrots on the countertop. About 15 feet away he says, “Honey, what’s for dinner?” Nothing. He gets halfway to her and repeats the same question. Nothing. Very concerned, he gets right behind her and asks again “What’s for dinner?”

She turns around and says “For the THIRD time, beef stew!”

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Q: What do you get when you cross a vampire with a snowman?

A: Frostbite!

6 0

3 years ago

based on what you wrote in the table in part a, what effect do lone pairs have on the bond angle? why do you think this happens?

umka21 [38]

Because they are more in close proximity to the core atom's nucleus than lone pairs are, lone pairs reject other lone pairs more strongly than bonding pairs do effect the bond angle.

When a single pair of electrons at the central atom begins to resist the bound pair of electrons, the bond angle decreases and the bonds are slightly shifted inward. It moves existing atoms closer together and modifies their geometry. It's equivalent to include an atom. When there is an increase in back bonding, the bond angle rises. Because the lone pair electrons of the two atoms reject one another, adjacent atoms in a molecule that have lone pair electrons will not be kept together in their bond as securely.

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6 0

2 years ago