Answer:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Explanation:
2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02
Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.
2KHCO3+ H3PO4 arrow K2HPO4 + H20 + C02
Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + C02
There are 2 carbons on the left. You need 2 on the right.
2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + 2C02
That should do it.
Let's make a table to show balance.
Species K H C PO4- O
Left 2 5 2 1 6 from CO3^(2-)
Right 2 5 2 1 6 from H2O/CO2
Answer:
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Explanation:
Given data:
Energy of photon = 1.10 × 10⁻¹³ J.
Wavelength of photon = ?
Solution:
Formula:
E = h.c / λ
λ = h. c / E
λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.
λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J
λ = 18.071 × 10⁻¹³ m
λ = 18.071 × 10⁻¹³ × 10⁹
λ = 18.071 × 10⁻⁴ nm
λ = 0.002 nm
The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.
Answer:
epidermal! hope this helps u!
Answer:
Percent yield = 94.62%
Explanation:
Given data:
Actual yield of BeBr₂ = 1.23 mol
Theoretical yield of BeBr₂ = 220 g
Percent yield = ?
Solution:
Theoretical yield in moles:
Number of moles = mass/molar mass
Number of moles = 220 g/168.82 g/mol
Number of moles = 1.30 mol
Percent yield:
Percent tiled = actual yield / theoretical yield × 100
by putting values,
Percent yield = 1.23 mol / 1.30 mol × 100
Percent yield = 0.9462 × 100
Percent yield = 94.62%
Answer:
2.08 moles
Explanation:
number of molecules = mass / molecular mass of SO₄
number of molecules = 200 g / 96.06 g/mol
number of molecules ≈ 2.08
